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3 years ago

5

Problem page a total of 420 tickets were sold for the school play. they were either adult tickets or student tickets. the number

of student tickets sold was two times the number of adult tickets sold. how many adult tickets were sold?

1 answer:

34kurt3 years ago

3 0

280 student tickets were sold

140 adult tickets were sold

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Q.3 Write the factors of 28 in circle A and the factors of 32 in circle B. Write

marissa [1.9K]

Answer: The largest common factor of 28 and 32 is 4.

Step-by-step explanation:

The factors of 28 are 1, 2, 4, 7, 14, 28

The factors of 32 are 1, 2, 4, 8, 16, 32

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2 years ago

What is the cheapest way to go to a ball game if the admissions options are as shown? A) $10 for a single B) $15 for a couple C)

vivado [14]

Answer: C

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3 years ago

What is the slope of a line perpendicular to the line y=-1/4x-1

ella [17]

-1/4
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4 0

3 years ago

Need answer to this math problem

Elis [28]

The slope of this line is the difference of the y values divided by the difference of the x values. Solving this give 4/-3. Then, you already know the b in y = mx+b, which is 2, because you already have the value (0, 2). So, the answer is y = $-\frac{4}{3}$ x + 2

8 0

3 years ago

Read 2 more answers

Alla [95]

$\bf \begin{array}{clclll}
3^{1001}&\qquad &4^{1002}\\
\uparrow &&\uparrow \\
a&&b
\end{array}\\\\
-----------------------------\\\\
(a+b)^2-(a-b)^2\implies (a^2+2ab+b^2)-(a^2-2ab+b^2)
\\\\\\
a^2+2ab+b^2-a^2+2ab-b^2\implies 2ab+2ab\implies 4ab
\\\\\\
now\qquad 4(3^{1001})(4^{1002})=k12^{1001}\qquad 
\begin{cases}
12^{1001}\\
(4\cdot 3)^{1001}\\
4^{1001}\cdot 3^{1001}
\end{cases}$

$\bf \\\\\\
4(3^{1001})(4^{1002})=k(4^{1001}\cdot 3^{1001})\implies \cfrac{4(3^{1001})(4^{1002})}{4^{1001}\cdot 3^{1001}}=k
\\\\\\
4\cdot \cfrac{3^{1001}}{3^{1001}}\cdot \cfrac{4^{1002}}{4^{1001}}=k\implies 4\cdot 4^{1002}4^{-1001}=k\impliedby 
\begin{array}{llll}
\textit{same base}\\
\textit{add the}\\
exponents
\end{array}
\\\\\\
4\cdot 4^{1002-1001}=k\implies 4\cdot 4^1=k\implies 16=k$

6 0

3 years ago