Question

The area of a rectangle is 36 square centimeters. The length is 1 foot more than twice the width.

Answer 1

I hope this helps you

Answer 2

Answer:

4 cm

Step-by-step explanation:

In order to solve this problem we just have to remember the formula for the area of the rectangle:

$A=L*W$

Now we have to represent the values for width and lenth, we are going to use X for the width, and if the length is twice as much the width and is one foot more it will be represented by: 2x+1

So if we put the values into the formula we get an equation:

$A=(x)(x+1)\\A=x^{2} +x\\36=x^{2} +x\\x^{2} +x-36=0$

Now that we have our equation we can solve by factorizing it:

$x^{2}+x-36=0\\ (x+9)(x-4)=0$

Once we have the two factors we just equalize them to 0

And solve it for (x-4):

$x-4=0\\x=4$

So the width of the rectangle is 4 and the length is 9.