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sdas [7]
3 years ago
13

A cheetah runs at a speed of 180 kmph. It covers a distance of 400 m in:​

Mathematics
1 answer:
Nutka1998 [239]3 years ago
4 0

Answer:

8 second

Step-by-step explanation:

400/180,000 × 3,600 second =

1,440,000/180, 000 = 8 second

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jolli1 [7]

Answer:

373

Step-by-step explanation:


5 0
3 years ago
Solve:​ ​9x - 2(4x + 5) = 2x - (4 - x) - 12 A 16 B 9 C 3 D 13
Margarita [4]

Step-by-step explanation:

4x+2x+x+9x=16x

16x=2+5+4=11

x=11

7 0
3 years ago
Which is the best first step when solving the following system of equations? x + y = 3. 4 x minus y = 7. Multiply the first equa
____ [38]

Answer:

just add the equation and solve it then the value of X could be found then put the value of X and the value of y can be found. Just like in the below

Step-by-step explanation:

X+y=3 ------------ equation 1

4x-y=7 ------------ equation 2

adding equation 1 and 2

X+y=3

+ 4x-y=7

-----------------

5x = 10

X = 10/5

X = 2

putting the value of X in equation 1

or, 2+y=3

or, y = 3-2

Thus, y = 1

7 0
2 years ago
Read 2 more answers
How would you solve this question?
skad [1K]
That I can not understand it looks weird.
8 0
2 years ago
Please help solve this system of equations
stepan [7]

Make a substitution:

\begin{cases}u=2x+y\\v=2x-y\end{cases}

Then the system becomes

\begin{cases}\dfrac{2\sqrt[3]{u}}{u-v}+\dfrac{2\sqrt[3]{u}}{u+v}=\dfrac{81}{182}\\\\\dfrac{2\sqrt[3]{v}}{u-v}-\dfrac{2\sqrt[3]{v}}{u+v}=\dfrac1{182}\end{cases}

Simplifying the equations gives

\begin{cases}\dfrac{4\sqrt[3]{u^4}}{u^2-v^2}=\dfrac{81}{182}\\\\\dfrac{4\sqrt[3]{v^4}}{u^2-v^2}=\dfrac1{182}\end{cases}

which is to say,

\dfrac{4\sqrt[3]{u^4}}{u^2-v^2}=\dfrac{81\times4\sqrt[3]{v^4}}{u^2-v^2}

\implies\sqrt[3]{\left(\dfrac uv\right)^4}=81

\implies\dfrac uv=\pm27

\implies u=\pm27v

Substituting this into the new system gives

\dfrac{4\sqrt[3]{v^4}}{(\pm27v)^2-v^2}=\dfrac1{182}\implies\dfrac1{v^2}=1\implies v=\pm1

\implies u=\pm27

Then

\begin{cases}x=\dfrac{u+v}4\\\\y=\dfrac{u-v}2}\end{cases}\implies x=\pm7,y=\pm13

(meaning two solutions are (7, 13) and (-7, -13))

8 0
2 years ago
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