Given , one container is filled with a mixture that is 30% acid a second container filled with a mixture that is 50% acid and the second container 50% larger than the first .

Let, the volume of first container is = x

Then , the volume of second container = (x+ x of 50%)

= x + 0.5 x

= 1.5 x

Therefore the amount of acid in first container $=x \times \frac{30}{100}$ = 0.3 x

The amount of acid in second container $=1.5x \times \frac{50}{100}$ = 0.75x

Total amount of acid= 0.3x + 0.75x = 1.05 x

Total amount of solution = x+1.5x = 2.5x

The amount of acid in third container is = $\frac{1.05x}{2.5x} \times 100%$ %

= 42%

4 0

3 years ago

There are 18 female students and 16 male students in a class. Which of the following expresses the ratio of female students to m

Alex Ar [27]

9:8
9 female to 8 male

6 0

2 years ago

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