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vlabodo [156]
4 years ago
9

A silk ribbon costs $5.60 for 0.8m. How much does 3.25m of this silk ribbon cost?

Mathematics
2 answers:
Varvara68 [4.7K]4 years ago
8 0
We can first find how much the ribbon cost for 1m by setting an equation.

Let $y be the cost for 1m:

0.8y = 5.60
y = 5.60 ÷ 0.8
y = 7

Now that we know 1m of ribbon cost $7, we can proceed to find how much 3.25m ribbon cost by mutiplying the length with the cost:

7 x 3.25
=$22.75

Therefore the answer is $22.75.

Hope it helps!
taurus [48]4 years ago
5 0

Answer:

$22.75

Step-by-step explanation:

#1) Find how much 1m of ribbon costs=  $5.60 divided by 0.8m= $7

#2) Look at how much does it cost for an amount of ribbon, 3.25m.

#3) Lastly, multiply $7 by 3.25 to equal to $22.75.

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Find two numbers that have a sum of 77.95 and a difference of 30.61
Alina [70]
<span>If you would like to know the values of these two numbers, you can calculate this using the following steps:<span>

a + b = 77.95
a - b = </span></span>30.61 ... a = 30.61 + b
________<span>_______________
a + b = 77.95
(30.61 + b) + b = 77.95
30.61 + 2 * b = 77.95
2 * b = 77.95 - 30.61
2 * b = 47.34    /2
b = </span>47.34<span> / 2
b = 23.67

a = </span>30.61 + b = 30.61 + 23.67<span> = 54.28

Result: The numbers are </span>23.67<span> and 54.28.</span>
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4 years ago
PRICES The Consumer Price Index (CPT) gives the relative price for a fixed set of goods and services. The CPI from
slavikrds [6]

Using function concepts, it is found that the turning points of the graph are:

  • November 2000, when it goes from increasing to decreasing.
  • December 2000, when it goes from decreasing to increasing.
  • June 2001, when it goes from increasing to decreasing.

In a graph:

  • A function is increasing if it is <u>pointing upwards.</u>
  • If it is <u>pointing downwards,</u> it is decreasing.
  • A turning point is when the function changes from <u>decreasing to increasing or vice-versa</u>.

In this problem:

  • Initially, the function is increasing.
  • In month 3, that is, November 2000, it starts to decrease, thus, in November 2000, we have a<u> turning point.</u>
  • The next month, that is, December 2000, it starts to increase again, so it is another <u>turning point</u>.
  • It increases until month 9, which is June 2001, when it starts to decrease, being the <u>final turning point.</u>

A similar problem is given at brainly.com/question/13539822

7 0
3 years ago
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sladkih [1.3K]

Answer:

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3 years ago
Which values of c will cause the quadratic equation –x2 3x c = 0 to have no real number solutions? check all that apply.
nika2105 [10]

The given quadratic equation will not have any real solution for c<-9/4.

The given quadratic equation is:

-x^{2} +3x+c=0

<h3>What is a quadratic equation?</h3>

Any equation of the form ax^{2} +bx+c=0 is called a quadratic equation with a≠0.

In order to have no real solution, the discriminant of a quadratic equation will be less than zero.

D < 0

3^{2} -4(-1)(c) < 0

9+4c < 0

c < -\frac{9}{4}

For c < -\frac{9}{4} the given quadratic equation will have no real solutions.

Hence, the given quadratic equation will not have any real solution for c<-9/4.

To get more about quadratic equations visit:

brainly.com/question/1214333

5 0
2 years ago
An elementary school is offering 3 language classes: one in Spanish, one in French,and one in German. The classes are open to an
Alona [7]

Answer:

A. 0.5

B. 0.32

C. 0.75

Step-by-step explanation:

There are

  • 28 students in the Spanish class,
  • 26 in the French class,
  • 16 in the German class,
  • 12 students that are in both Spanish and French,
  • 4 that are in both Spanish and German,
  • 6 that are in both French and German,
  • 2 students taking all 3 classes.

So,

  • 2 students taking all 3 classes,
  • 6 - 2 = 4 students are in French and German, bu are not in Spanish,
  • 4 - 2 = 2 students are in Spanish and German, but are not in French,
  • 12 - 2 = 10 students are in Spanish and French but are not in German,
  • 16 - 2 - 4 - 2 = 8 students are only in German,
  • 26 - 2 - 4 - 10 = 10 students are only in French,
  • 28 - 2 - 2 - 10 = 14 students are only in Spanish.

In total, there are

2 + 4 + 2 + 10 + 8 + 10 +14 = 50 students.

The classes are open to any of the 100 students in the school, so

100 - 50 = 50 students are not in any of the languages classes.

A. If a student is chosen randomly, the probability that he or she is not in any of the language classes is

\dfrac{50}{100} =0.5

B. If a student is chosen randomly,  the probability that he or she is taking exactly one language class is

\dfrac{8+10+14}{100}=0.32

C. If 2 students are chosen randomly,  the probability that both are not taking any language classes is

0.5\cdot 0.5=0.25

So,  the probability that at least 1 is taking a language class is

1-0.25=0.75

3 0
4 years ago
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