All categories

2 years ago

Given cosθ=3√3 and sinθ<0 . What is the value of sinθ ?

Mathematics

1 answer:

guapka [62]2 years ago

7 0

Answer:

Doesn't make sense.

Step-by-step explanation:

-1 ≤ cosθ ≤ 1

=> cosθ = 3√3 doesn't make sense.

You might be interested in

NECESITO AYUDA EN ESTOS EJERCIICIOS DE MATES NIVEL SEGUNDO ESO

Kay [80]

Answer: 49/60

Step-by-step explanation:

(1/3+2/5)-1/4-(5/6-7/6)

Primero (5/6-7/6)

5/6-7/6=-2/6

1/3+2/5-1/4-(-2/6)

1/3+2/5-1/4+2/6

2/6=1/3

1/3+2/5-1/4+1/3

2/3+2/5-1/4

2/3=10/15

2/5=6/15

10/15+6/15-1/4

16/15-1/4

16/15=64/60

1/4=15/60

64/60-15/60=49/60

4 0

3 years ago

Can anyone help me with this

Nataliya [291]

To find surface area, we can use the equation:

SA=2lw+2wh+2lh, where:
l=10 in
w=3 in
h=7 in

SA=(2)(10)(3)+(2)(3)(7)+(2)(10)(7)
SA=60+42+140
SA=242 in²

5 0

3 years ago

What is the measure of the other acute angle ?

Vaselesa [24]

Answer:

$62^{o}$

Step-by-step explanation:

All the angles in a triangle add up to $180^{o}$

Every right angle triangle has a right angle in it which is $90^{o}$

So to find the remaining angle, you do $180^{o}$ - $90^{o}$ - $28^{o}$ = $62^{o}$

7 0

2 years ago

The number of bacteria in a certain culture doubled every hour. If there were 30 bacteria present in the culture initially, how

vichka [17]

Answer:

The number of bacteria after $8th$ will be $3840$

Step-by-step explanation:

Given the initially 30 bacteria present in the culture.

Also, the number of bacteria got doubled every hour.

So, using the equation

$A=A_0r^{n-1}$

Where $A$ is number of bacteria after $n$ hours.

$A_0$ is bacteria present initially.

$r$ is the common ration, in our problem it is given that bacteria doubles every hour. So, $r=2$

And $n$ is the number of hours. In our problem we need amount of bacteria at the end of $8th$ hours. So, $n=8$

Plugging values in the formula we get,

$A=30(2)^{8-1}\\A=30\times 2^7\\A=30\times 128\\A=3840$

So, number of bacteria after $8th$ will be $3840$

3 0

3 years ago

How much energy in joules can the solar panel produce each day if solar cells were 100% efficient and generate 1000 watts of pow

notsponge [240]

Answer:

The solar panel produce 6.48 × 10⁶ J of energy each day.

Step-by-step explanation:

If the solar cells were 100% efficient and generate 1000 watts of power per square meter

The power generated per square meter will be

$\frac{100}{100} \times 1000 watts/m^{2}$

= 1000 watts/m²

This is the power that would be generated per square meter if the solar cells were 100% efficient.

Now, for a 1 square meter panel of solar cells with an efficiency of 30%, the power generated will be

$\frac{30}{100} \times 1000 watts/m^{2} \times 1m^{2}$

= 300 watts

This is the power that would be generated by a 1 square meter panel of solar cells with an efficiency of 30%

Now, to determine the energy in joules (J) that the solar panel produce each day

We can determine the energy from the formula

Energy = Power × time

From the question, the solar cells receives the equivalent of 6 hours of direct sunlight per day, that is

Time = (6 × 60 × 60) secs = 21600 secs

Hence,

Energy = 300 watts × 21600 secs

Energy = 6480000 Joules

Energy = 6.48 × 10⁶ J

8 0

3 years ago

Read 2 more answers