Answer:
Part a) The distance on a map between Joseph's house and the airport is 2.53 inches
Part b) The distance on a map between the airport and the restaurant is 1.68 inches and the total distance on a map between Joseph's house and the restaurant is 4.21 inches
Step-by-step explanation:
Part a) The actual distance between Joseph's house and the airport is 24 miles. How far apart are Joseph's house and the airport on the map?
we know that
The scale of a map is 1 inch : 9.5 miles
so
using proportion
Find the distance on a map if the actual distance between Joseph's house and the airport is 24 miles
Let
x-----> the distance on a map
1/9.5=x/24
x=24/9.5=2.53 inches
Part b) Joseph traveled from his house to the airport. He then traveled another 16 miles past the airport to a restaurant. How many inches on the map represent this distance?
we know that
The scale of a map is 1 inch : 9.5 miles
so
using proportion
Find the distance on a map if the actual distance between airport to the restaurant is 16 miles
Let
x-----> the distance on a map
1/9.5=x/16
x=16/9.5=1.68 inches
The total distance on a map between Joseph's house and the restaurant is equal to
2.53 inches+1.68 inches=4.21 inches
The answer of average rate o change is 2. Hope it help!
Answer: If this isn't a trick question it is $68.60
Step-by-step explanation: You just multiply the 98 cents by the 70 songs.
Answer:
4 batches:
cups
7 batches:
cups
Step-by-step explanation:
If he uses 2/3 cup of flour for <u>each</u> batch, then that is 2/3 four times, or 2/3 · 4.
× 
=
= 
If he makes three more, than that will be 7 batches in total. We can multiply 2/3 by 3 to find out how much will be needed for those extra three, then add that product to
.
× 
=
= 2
= 
Thus,
and
are the answers.
hope this helps!