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3 years ago

Whats an equation for (0,75) (7,40) in slope intercept form

Mathematics

1 answer:

Molodets [167]3 years ago

8 0

The slope-intercept form: y = mx + b.

m - slope, b - y-intercept

$m=\dfrac{y_2-y_1}{x_2-x_1}$

We have the points (0, 75) → y-intercept (b = 75), and (7, 40).

Substitute the coordimates of the points to the formula of a slope:

$m=\dfrac{40-75}{7-0}=\dfrac{-35}{7}=-5$

<h3>Answer: y = -5x + 75.</h3>

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If LM = MK, LK =7x-10, KN = x+3, MN = 9x-11, and KJ =28, find LJ

marusya05 [52]

Answer:

Step-by-step explanation:

Suppose J, K, L, M, N are points on the same line.

MK = MN + (-KN) = MN - KN = 9x - 11 - x - 3 = 8x - 14

Since LK = MK and LK = 7x - 10, then

7x - 10 = 8x - 14

8x - 7x = -10 + 14

x = 4

LJ = MK + KJ

MK = LK = 7x - 10 = 7(4) - 10 = 28 - 10 = 18

LJ = 18 + 28 = 46

Read more on Brainly.com - brainly.com/question/5067118#readmore

8 0

3 years ago

Read 2 more answers

Math algebra 2 show you’re work plz

LenKa [72]

9514 1404 393

Answer:

(t, u, w) = (1, -2, -2)

Step-by-step explanation:

A graphing calculator makes short work of this, giving the solution as ...

(t, u, w) = (1, -2, -2)

There are many ways to solve this "by hand." Here's one of them.

Add the first and third equations. Their sum is ...

-3t +4w = -11 . . . . . [eq4]

Add this to twice the second equation. That sum is ...

(-3t +4w) +2(-4t -2w) = (-11) +2(0)

-11t = -11

t = 1

Substituting this into the second equation gives ...

-4(1) -2w = 0

w +2 = 0 . . . . divide by -2

w = -2 . . . . add -2

Substituting for t in the third equation lets us find u.

2(1) -2u = 6

-1 +u = -3 . . . . . divide by -2

u = -2 . . . . add 1

The solution is (t, u, w) = (1, -2, -2).

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3 years ago

The Smith house payments are 800$ per month. What percent of their combined take home pay goes for the house payments? (96,169 i

Nat2105 [25]

If $96,169 is their combined pay in one year then consider this...
800x12=9,600

Simplify 96,169 to 96,000...

Divide 96,000 by 9,600 = 10.0
then pretend we had divided 96,100 by 9,600 then your answer would be 10.01

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3 years ago

A runner moves 8 miles every 1 minute. Write and graph an equation in two variables that shows the relationship between time and

Mila [183]

Answer:

what grade is this?

Step-by-step explanation:

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3 years ago

Initially 100 milligrams of a radioactive substance was present. After 6 hours the mass had decreased by 3%. If the rate of deca

Hitman42 [59]

Answer:

The half-life of the radioactive substance is 135.9 hours.

Step-by-step explanation:

The rate of decay is proportional to the amount of the substance present at time t

This means that the amount of the substance can be modeled by the following differential equation:

$\frac{dQ}{dt} = -rt$

Which has the following solution:

$Q(t) = Q(0)e^{-rt}$

In which Q(t) is the amount after t hours, Q(0) is the initial amount and r is the decay rate.

After 6 hours the mass had decreased by 3%.

This means that $Q(6) = (1-0.03)Q(0) = 0.97Q(0)$ . We use this to find r.

$Q(t) = Q(0)e^{-rt}$

$0.97Q(0) = Q(0)e^{-6r}$

$e^{-6r} = 0.97$

$\ln{e^{-6r}} = \ln{0.97}$

$-6r = \ln{0.97}$

$r = -\frac{\ln{0.97}}{6}$

$r = 0.0051$

$Q(t) = Q(0)e^{-0.0051t}$

Determine the half-life of the radioactive substance.

This is t for which Q(t) = 0.5Q(0). So

$Q(t) = Q(0)e^{-0.0051t}$

$0.5Q(0) = Q(0)e^{-0.0051t}$

$e^{-0.0051t} = 0.5$

$\ln{e^{-0.0051t}} = \ln{0.5}$

$-0.0051t = \ln{0.5}$

$t = -\frac{\ln{0.5}}{0.0051}$

$t = 135.9$

The half-life of the radioactive substance is 135.9 hours.

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3 years ago