2+½, is just 2½, now divided by 1/4.
let's first convert the mixed fraction to improper, and then divide.
![\bf \stackrel{mixed}{2\frac{1}{2}}\implies \cfrac{2\cdot 2+1}{2}\implies \stackrel{improper}{\cfrac{5}{2}} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{5}{2}\div \cfrac{1}{4}\implies \cfrac{5}{2}\cdot \cfrac{4}{1}\implies \cfrac{5}{1}\cdot \cfrac{4}{2}\implies 5\cdot 2\implies 10](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7Bmixed%7D%7B2%5Cfrac%7B1%7D%7B2%7D%7D%5Cimplies%20%5Ccfrac%7B2%5Ccdot%202%2B1%7D%7B2%7D%5Cimplies%20%5Cstackrel%7Bimproper%7D%7B%5Ccfrac%7B5%7D%7B2%7D%7D%0A%5C%5C%5C%5C%5B-0.35em%5D%0A~%5Cdotfill%5C%5C%5C%5C%0A%5Ccfrac%7B5%7D%7B2%7D%5Cdiv%20%5Ccfrac%7B1%7D%7B4%7D%5Cimplies%20%5Ccfrac%7B5%7D%7B2%7D%5Ccdot%20%5Ccfrac%7B4%7D%7B1%7D%5Cimplies%20%5Ccfrac%7B5%7D%7B1%7D%5Ccdot%20%5Ccfrac%7B4%7D%7B2%7D%5Cimplies%205%5Ccdot%202%5Cimplies%2010)
For this case we have the following equation:
Q = Av
Where the area is given by:
A = pi * r ^ 2
A = pi * (d / 2) ^ 2
A = (pi / 4) * d ^ 2
Substituting we have:
Q = ((pi / 4) * d ^ 2) v
From here, we clear the diameter:
d = root ((4 / pi) * (Q / v))
Substituting values we have:
d = root ((4 / pi) * (50/600))
d = 0.36 feet
Answer:
The diameter of a pipe that allows a maximum flow of 50ft ^ 3 / min of water flowing at a velocity of 600ft / min is:
d = 0.36 feet
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The answer to this question would be: 300; 20; 150; 10
When you multiply 15 x 32, you can divide both numbers into this:
15= 10 + 5
32= 30 +2
Then the multiplication becomes (10+5) * (30+2) which will result in 4 partial product like this:
10*30= 300
10* 2= 20
5* 30= 150
5* 2= 10
