Answer:
∴35.97 mg caffeine would be left in the system after 5 hours.
Step-by-step explanation:
Given that,
A cup of coffee has approximately 310 mg of caffeine.
Caffeine decrease at a rate 35% per hour.
Exponential Function:
y(t)= Amount caffeine after t hours
= Initial amount of caffeine
r= rate of decrease
t = Time in hour.
Here y(t)=?, = 310 mg, r=35%=0.35, t= 5 hours
=35.97 mg
∴35.97 mg caffeine would be left in the system after 5 hours.
Answer: 70.909090909091%
Step-by-step explanation: Reading through the problem we have <em>78 is</em>, that's 78 equals, <em>what percent</em>, x/100, <em>of 110</em>, times 110.
It's important to understand that <em>percent</em> means over 100 so what percent would simply mean <em>x/100</em> or any variable but I will be using x.
So we have the equation
So cross canceling the 110 and 100 to 11 and 10, we have
Multiply both sides by 10 to get rid
of the fraction and we have 780 = 11x.
Now divide both sides by 11 and 70.909090909091 = x.
So, 78 is 70.909090909091% of 110.
Work is attached in the image provided.
