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2 years ago

Question 23 of 23

Mathematics

1 answer:

Nezavi [6.7K]2 years ago

8 0

Answer:

Step-by-step explanation:

The change in x from A to B is 12, and 1/4 of this is 3.

Adding this to the x coordinate of A, we get 0.

The only option with an x coordinate of 0 is D.

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Use the multiplication property of equality to multiply both sides of the equation by 1/6 to get: (1/6)6x=(1/6)48.

zzz [600]

X= 8 because by multiplying the fraction with a whole number you had to to convert it to i a fraction and that equals one and then 1/6 times 48 is 8

5 0

2 years ago

What is the correct order of the fractions from least to greatest? Point A: −11 3 Point B: −2 3 Point C: 1 3 Point D: −12 3 The

Otrada [13]

Answer

-12/3, -11/3, -2/3, 1/3

Step-by-step explanation:

sorry if im wrong

6 0

2 years ago

Read 2 more answers

WHICH RATIO SHOW PORTION FORM WITH 25/28 BY WRITING IN LOWEST FORM

miss Akunina [59]

25/28

is in it's lowest form, as it cannot be reduced anymore.

25/28 = 0.8928571

hope this helps

8 0

3 years ago

What property is -3 + 3 = 0

raketka [301]

Answer to question:

inverse property
“Staying the same”
adding a number to itself results in a sum of zero

4 0

3 years ago

Read 2 more answers

A researcher claims that the variation in the salaries of elementary school teachers is greater than the variation in the salari

guajiro [1.7K]

Answer:

The null hypothesis is $H_o : \sigma^2_1 = \sigma^2 _2$

The alternative hypothesis is $H_a : \sigma_1 ^2 > \sigma^2_2$

$F_{critical} = 1.8608$

$F = 2.9085$

The decision rule is

Reject the null hypothesis

There is sufficient evidence to support the researchers claim

Step-by-step explanation:

From the question we are told that

The first sample size is $n_1 = 30$

The sample variance for elementary school is $s^2_1 = 8324$

The second sample size is $n_2 = 30$

The sample variance for the secondary school is $s^2_2 = 2862$

The significance level is $\alpha = 0.05$

The null hypothesis is $H_o : \sigma^2_1 = \sigma^2 _2$

The alternative hypothesis is $H_a : \sigma_1 ^2 > \sigma^2_2$

Generally from the F statistics table the critical value of $\alpha = 0.05$ at first and second degree of freedom $df_1 = n_1 - 1 = 30 - 1 = 29$ and $df_2 = n_2 - 1 = 30 - 1 = 29$ is

$F_{critical} = 1.8608$

Generally the test statistics is mathematically represented as

$F = \frac{s_1^2 }{s_2^2}$

=> $F = \frac{8324 }{2862}$

=> $F = 2.9085$

Generally from the value obtained we see that $F > F_{critical }$ Hence

The decision rule is

Reject the null hypothesis

The conclusion is

There is sufficient evidence to support the researchers claim

4 0

2 years ago