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djyliett [7]
2 years ago
15

The mayor of a town has proposed a plan for the annexation of an adjoining community. A political study took a sample of 900 vot

ers in the town and found that 75% of the residents favored annexation. Using the data, a political strategist wants to test the claim that the percentage of residents who favor annexation is above 72%. Testing at the 0.05 level, is there enough evidence to support the strategist's claim
Mathematics
1 answer:
Stells [14]2 years ago
3 0

Answer:

z=\frac{0.75 -0.72}{\sqrt{\frac{0.72(1-0.72)}{900}}}=2.00  

Now we can calculate the p value. Since is a bilateral test the p value would be:  

p_v= P(Z>2) =0.0228

Since the p value is lower than the significance level of 0.05 we have enough evidence to conclude that the true proportion of residents favored annexation is higher than 0.72 or 72%

Step-by-step explanation:

Information given

n=900 represent the random sample selected

\hat p=0.75 estimated proportion of residents favored annexation

p_o=0.72 is the value that we want to test

represent the significance level

z would represent the statistic

p_v represent the p value

Hypothesis to test

The political strategist wants to test the claim that the percentage of residents who favor annexation is above 72%.:  

Null hypothesis:p\leq 0.72  

Alternative hypothesis:p > 0.72  

The statistic for this case is given by:

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

Replacing the data given we got:

z=\frac{0.75 -0.72}{\sqrt{\frac{0.72(1-0.72)}{900}}}=2.00  

Now we can calculate the p value. Since is a bilateral test the p value would be:  

p_v= P(Z>2) =0.0228

Since the p value is lower than the significance level of 0.05 we have enough evidence to conclude that the true proportion of residents favored annexation is higher than 0.72 or 72%

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