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3 years ago

Determine whether the given lengths form a right triangle.21 cm, 28 cm, 35 cm

Mathematics

1 answer:

lord [1]3 years ago

5 0

U have to add them all together

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Can i get help please ?

wariber [46]

Answer:

D -- the last one

Step-by-step explanation:

The formula tells you what to do.

t = 3

A0 = 25

A(t) = ?

A(3) = 25 * (1/2)^3

A(t) = 25 * 1/8

A(t) = 25/8

A(t) = 3.125

4 0

3 years ago

Johnathan has 2500 kg of sand delivered to a construction site every day. About how many tons of sand does he have delivered to

sp2606 [1]

C 77.2 tons for four weeks

7 0

3 years ago

Read 2 more answers

PLEASE HELP WILL GOVE BRAINLY

Travka [436]

The rate of change is constant because of how they change 2 numbers differently each time they go per X, such as 1 for going up one x, if it was 2+, then the next would be adding 3 onto that next number. And so on.

3 0

3 years ago

Intelligence quotients (IQs) measured on the Stanford Revision of the Binet Simon Intelligence Scale are normally distributed w

nevsk [136]

Answer:

the percentage of people who have an IQ between 115 and 140 is 16.79%

Step-by-step explanation:

From the information given:

We are to determine the percentage of people who have an IQ between 115 and 140.

i.e

P(115 < X < 140) = P( X ≤ 140) - P( X ≤ 115)

$P(115 < X < 140) = P( \dfrac{X-100}{\sigma}\leq \dfrac{140-100}{16})-P( \dfrac{X-100}{\sigma}\leq \dfrac{115-100}{16})$

$P(115 < X < 140) = P( Z\leq \dfrac{140-100}{16})-P( Z\leq \dfrac{115-100}{16})$

$P(115 < X < 140) = P( Z\leq \dfrac{40}{16})-P( Z\leq \dfrac{15}{16})$

$P(115 < X < 140) = P( Z\leq 2.5)-P( Z\leq 0.9375)$

$P(115 < X < 140) = P( Z\leq 2.5)-P( Z\leq 0.938)$

From Z tables :

$P(115 < X < 140) = 0.9938-0.8259$

$P(115 < X < 140) = 0.1679$

Thus; we can conclude that the percentage of people who have an IQ between 115 and 140 is 16.79%

3 0

3 years ago

Rent is $1,258. Phone charges last month were $46.88. Groceries cost about $115/week. What is a good estimate of your monthly ex

oksano4ka [1.4K]

If these are the only expenses you have, a good estimate would be $1765

6 0

3 years ago