On the coordinate plane below, Point P, is located at (2,-3) and point Q is located at (-4,4). Find the distance between points,
P and Q
1 answer:
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Answer:
feet
Step-by-step explanation:
The depth of the fish to the surface of water at 1:00 pm = 2 feet
= feet
The depth of the fish to its initial position at 4:00 pm = 3 feet
= feet
The position of the fish with respect to the water's surface at 4:00 pm = the depth of the fish to the surface of water at 1:00 pm + the depth of the fish to its initial position at 4:00 pm
= +
=
=
The position of the fish with respect to the water's surface at 4:00 pm is feet.
Answer:
Step-by-step explanation:
sin A =
Sin 29 =
0.4848 * 500 = y
y = 242.4 ft