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3 years ago

Please help!! Use line plot to help.

Mathematics

1 answer:

muminat3 years ago

3 0

2. is 4/2 or 2 3.is 12/4 or 3 4.is 5 wholes

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Which graph represents the piecewise-defined function? y={−45x−3 if x<03x−10 if x≥2

Nikitich [7]

Step-by-step explanation:

$y=\left \Bigg\{ {\big{-45x-3 \qquad x < 0} \atop \big{3x - 10 \qquad x \geq2 }} \right.$

$\begin {array}{c|c}{ x&y}}\\ -\infty&-\infty\\-2&-93\\-1&-48\\ 0 &-3^*\\1&nothing\\2&-4\\3&-1\\4&2\\ \infty&\infty\\\end{array}$

* open dot

You did not provide the graphs to choose from so use the table above to determine which graph fits those coordinates.

Make sure that:

(0, -3) has an open dot
nothing is plotted between x = 0 and x = 2
(2, -4) has a closed dot

3 0

3 years ago

A television regularly selling for $500 is marked down to $300.

Igoryamba

He saves $200 (the amount of change over the original amount $500

200/500 = 2/5 and 2/5 = 40% (divide 2 by 5 and get .4 which = 40%)

40% discount is the answer to your question

3 0

3 years ago

if you roll a standard six-sided die what is the probability that you get a one or a five give your answer as a simplified fract

kondor19780726 [428]

Answer:

2/6 - simplified fraction=1/3

Step-by-step explanation:

5 0

3 years ago

How many solutions does

Nikolay [14]

Answer:

A no solution

Step-by-step explanation:

y = 2x + 10

3y - 6x = 30

3(2x+10) -6x =30

6x +30 -6x =30

6x -6x = 30-30

0=0

3 0

2 years ago

Jane wishes to bake an apple pie for dessert. The baking instructions say that she should bake the pie in an oven at a constant

Viktor [21]

Answer:

Therefore $k= \frac{ln2 }{18}$ , A=184

Step-by-step explanation:

Given function is

$T(t)=230 -e^{-kt}$

where T(t) is the temperature in °C and t is time in minute and A and k are constants.

She noticed that after 18 minutes the temperature of the pie is 138°C

Putting T(t) =138°C and t= 18 minutes

$138=230 -Ae^{-k\times 18}$

$\Rightarrow -Ae^{-18k}=138-230$

$\Rightarrow Ae^{-18k}=92$ .....(1)

Again after 36 minutes it is 184°C

Putting T(t) =184°C and t= 36 minutes

$184=230-Ae^{-k\times 36}$

$\Rightarrow Ae^{-36k}=230-184$

$\Rightarrow Ae^{-36k}=46$ .......(2)

Dividing (2) by (1)

$\frac{Ae^{-36k}}{Ae^{-18k}}=\frac{46}{92}$

$\Rightarrow e^{-18k}=\frac{46}{92}$

Taking ln both sides

$ln e^{-18k}=ln\frac{46}{92}$

$\Rightarrow -18k =ln (\frac12)$

$\Rightarrow -18k= ln1-ln2$

$\Rightarrow k= \frac{ln2 }{18}$

Putting the value k in equation (1)

$Ae^{-18\frac{ln2}{18}}=92$

$\Rightarrow A e^{ln2^{-1}}=92$

$\Rightarrow A.2^{-1}=92$

$\Rightarrow \frac{A}{2}=92$

$\Rightarrow A= 92 \times 2$

⇒A= 184.

Therefore $k= \frac{ln2 }{18}$ , A=184

7 0

3 years ago