I believe it's B. I hope this helps
Length of the original ribbon = 2/3 yard
Length of the ribbon in which the actual ribbon has to be cut = 1/12 yards
The above information's are already given in the question. It is required to find the number of pieces that the ribbon can be cut with the length that is already mentioned.
Then
Number of pieces that will be there = (2/3)/(1/12)
= (2 * 12)/3
= 24/3
= 8
So the actual ribbon can be cut into 8 pieces and each piece will have a length of 1/12 yards. Hopefully the procedure for doing this problem is clear to you. this is the easiest method for attempting these kind of problems.
Answer:
The need of help. I think that in some way, since Algebra can be quite difficult to understand students ask questions need help in order to understand more.
<span>√20 + 6√5
= </span><span>√(4 * 5) + 6√5
= 2</span><span>√5 + 6√5
= </span>√5 (2 + 6)
= 8√5
Hope it helps
If she lost 1/3 of her bows and still had 42, that means she had 63 bows before school because 1/3 of 63 is 21 and 63-21=42. If she got 7 for her birthday then 63-7=56. She had 56 bows before her birthday