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Anna [14]
3 years ago
14

What is 4 4/9 times 4

Mathematics
2 answers:
andrezito [222]3 years ago
8 0

Answer:

17 7/9

Step-by-step explanation:

4 4/9 times 4

4 x 4 = 16

4/9 x 4 = 16/9 = 1 7/9

= 16 + 1 7/9

= 17 7/9

Illusion [34]3 years ago
6 0
The answer is 5.777778 or 5.80 or 52 / 9 or 5 7/9 found by my calculator and decimal-fraction converter. MY ANSWER IS ACTUALLY CORRECT.
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Solve the equation 12+ 0.35×=20.05
lbvjy [14]
12 + 0.35X = 20.05
12 + 0.35X - 12 = 20.05 - 12
0.35X = 8.05 
0.35X/0.35 = 8.05/0.35
X = 23
Hope this helps!! 
8 0
3 years ago
Graph the given function.
SpyIntel [72]

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(got it right on edmentum)

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2 years ago
select the correct answer consider these functions f(x)=3x-7 g(x)=X +1/x-1 what is the value of f(g(3))
Alexeev081 [22]

Answer:

Me and my massive brain, among other massive things of mine, believe it to be -1

Step-by-step explanation:

6 0
3 years ago
the area of a rectangular field 4641 m squared. If the width of the field is 51 m, what is its length?
shusha [124]

✧・゚: *✧・゚:*    *:・゚✧*:・゚✧

                  Hello!

✧・゚: *✧・゚:*    *:・゚✧*:・゚✧

❖ The length of the field is 91 m.

Divide to find the missing length:

4641 ÷ 51 = 91

~ ʜᴏᴘᴇ ᴛʜɪꜱ ʜᴇʟᴘꜱ! :) ♡

~ ᴄʟᴏᴜᴛᴀɴꜱᴡᴇʀꜱ

5 0
3 years ago
Read 2 more answers
Suppose we have an unfair coin that its head is twice as likely to occur as its tail. a)If the coin is flipped 3 times, what is
Alenkinab [10]

Answer: a) 0.2222, b) 0.3292, c) 0.1111

Step-by-step explanation:

Since we have given that

Let the probability of getting head be p.

Since,  its head is twice as likely to occur as its tail.

p+\dfrac{p}{2}=1\\\\\dfrac{3p}{2}=1\\\\p=\dfrac{2}{3}

a)If the coin is flipped 3 times, what is the probability of getting exactly 1 head?

So, here, n  = 3

p=\dfrac{2}{3}

q=\dfrac{1}{3}

Now,

P(X=1)=^3C_1(\dfrac{2}{3})^1(\dfrac{1}{3})^2=0.2222

b)If the coin is flipped 5 times, what is the probability of getting exactly 2 tails?

2 tails means 3 heads.

So, it becomes,

P(X=3)=^5C_3(\dfrac{2}{3})^3(\dfrac{1}{3})^2=0.3292

c)If the coin is flipped 4 times, what is the probability of getting at least 3 tails?

P(X\leq 1)=\sum _{x=0}^1^4C_x(\dfrac{2}{3}^x(\dfrac{1}{3})^{4-x}=0.1111

Hence, a) 0.2222, b) 0.3292, c) 0.1111

8 0
3 years ago
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