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jenyasd209 [6]
3 years ago
15

The Satya Vansh become an important dynasty in the world of ​

Mathematics
1 answer:
Elanso [62]3 years ago
6 0

Answer: it’s 352425262625251452 is 4th of July and I am present

Step-by-step explanation:

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Find the missing side. Round<br> to the nearest tenth.<br> Х<br> y<br> 390<br> 57<br> X=[?]
sweet [91]

Answer:It's 46.2

Step-by-step explanation:

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3 years ago
What is the partial derivative of a given function
Marizza181 [45]
Partial differentiation of a function with more than one variables refers to its derivative being taken with respect to one of those variables, while the rest being held as a constant.

An example is the volume of a cylinder given by:
V(h, r) = \pi r^{2}h

The volume requires two variables in order to work out the volume, namely the radius and the height.

Using partial differentiation, its partial derivative can become:
\frac{\partial V}{\partial r} = 2\pi rh

This symbol is used in place of the derivative symbol, in order to distinguish total derivatives and partial derivatives.
7 0
3 years ago
Which is the correct algebraic expression for the following phase? 2.5 times as many pages​
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Answer:

Step-by-step explanation:

which is the correct algebraic expression for the following phase? 2.5 times as many pages

3x + 4y – 7,  4x – 10, etc.

7 0
3 years ago
Determine the equation of the line that passes through the points of intersection of the graphs of the quadratic functions f(x)
timofeeve [1]

Answer:x-2y-2=0

Step-by-step explanation:

Given :

f(x) = x^2 - 4 \\ g(x) = - 3x^2 + 2x + 8

Point of intersection :

f(x)=g(x)\\x^2-4=-3x^2+2x+8\\4x^2-2x-12=0\\2x^2-x-6=0\\2x^2-4x+3x-6=0\\2x(x-2)+3(x-2)=0\\(x-2)(2x+3)=0\\x=2\,,\,\frac{-3}{2}

x=2\,;f(2)=2^2-4=0\\x=\frac{-3}{2}\,; f\left ( \frac{3}{2} \right )=\left ( \frac{3}{2} \right )^2-4=\frac{-7}{4}=-1.75

So, we have points \left ( 2,0 \right )\,,\,\left ( -1.5,-1.75\ \right )

Equation of line passing through two points \left ( x_1,y_1 \right )\,,\,\left ( x_2,y_2 \right ) is given by y-y_1=\frac{y_2-y_1}{x_2-x_1}\left ( x-x_1 \right )

Let \left ( x_1,y_1 \right )=\left ( 2,0 \right )\,,\,\left ( x_2,y_2 \right )=\left ( -1.5,-1.75\ \right )

So, equation is as follows :

y-0=\frac{-1.75-0}{-1.5-2}\left ( x-2 \right )\\y=\frac{-1.75}{-3.5}\left ( x-2 \right )\\y=\frac{1}{2}(x-2)\\2y=x-2\\x-2y-2=0

4 0
4 years ago
BRAINLIEST IF YOU GET IT RIGHT
Gennadij [26K]
C is the answer. Hope that helps C:lol
5 0
3 years ago
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