The standard equation is 4p(x-h) = (y-k)^2 where |p| = focal distance |4p| = focal width.
<span>x=-1/8y^2
-8x=y^2
4*(-2)(x-0) =( y-0)^2
p = -2, h=0, k=0</span><span>
focal width = |4*(-2)| = 8
The answer to your question is that the length of the focal width is equal to 8.</span>
Answer:
TQ = 10
Step-by-step explanation:
The diagonal divides the square into 2 right triangles with the diagonal being the hypotenuse.
Using Pythagoras' identity in triangle TPQ
TQ² = PQ² + PT²
TQ² = 10² + 10² = 100 + 100 = 200 ( take square root of both sides )
TQ = 
= 
= 
× = 10
<h2><u>
Answer With Explanation:</u></h2>
<u>Firstly, let's start with <XOZ: =55°</u>
We know that <ZOQ is 70° and angles on a line add up to 180° so we do 180-70=110 110 divided by 2 = 55 so the 2 angles (XOZ & XOP are 55)
<u>Secondly, <OMN, <MON & <ONM = All are 60°</u>
These 2 angles are joined to create an equilateral triangle which always adds up to 180°
So, there are 3 points to this triangle, therefore we divide 180 by 3 which is 60. The angles are 60°
<u>Thirdly, <QON: =55°</u>
This angle lies on the line XON which needs to add up to 180°
As we worked out before, <XOZ was 55°
So, <ZOQ was already given as 70°
We then do 55+70=125 then 180-125=55°
<QON is 55°
(I'm only in Grade 9 LOL)
Answer:
He did the complete opposite of what he needed to do
Step-by-step explanation:
The error is that when you need to find x - intercept, you need to replace the value of y with zero, not the y value.
Cause otherwise, what he did here is to find the y - intercept
If you have any questions about the way I solved it, don't hesitate to ask me in the comments below :)
