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2 years ago

PLEASE HELPP! A square has an area of 5.76cm². Find the perimeter of the square

1 answer:

4 0

The ar. of square =X^
=5.76
So,X=√5.76
=2.4
now, perimeter of square =4(X)
=4(2.4)
=9.6
So, the perimeter of the square is 9.6cm..

Thanks!

Hope it helps you..

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2 years ago

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3 years ago

what is the rate of change for the linear relationship modeled in the table? x y −1 10 1 9 3 8 5 7 -1/2 0 1/2 2

Vesnalui [34]

Answer:

Rate of change for the linear relationship modeled is $\dfrac{-1}{2}$

Step-by-step explanation:

As the there is a linear relationship in the points, so all these points will be on a single straight line. Hence the slope will be same throughout all the points.

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7 0

3 years ago

Read 2 more answers

Which expression is equivalent to (x^2 -8) - (-2x^2+4)?

Phoenix [80]

Answer:

D) 3x^2 - 12

Step-by-step explanation:

Using PEMDAS;

There is no need to evaluate the part of the equation (x^2 - 8) because is no need to, as it is already in its simplest form.

We must evaluate the part of the equation continuing with, "- (-2x^2+4)," as it is not in its simplest form.

Evaluating "- (-2x^2+4)":

Step 1: Distributing the negative

Once distributing the negative symbol amongst the values within the parenthesis according to PEMDAS, we get "2x^2 - 4" as the product.

Step 2: Consider the rest of the equation to evaluate

Since the part of the equation is still in play here as it is a part of the original equation to be solved, we must evaluate it as a whole to get the final answer.

Thus,

x^2 -8 + 2x^2 - 4 = ___

*we can remove the parenthesis as it has no purpose, since it makes no difference.

Evaluating for the answer, we get,

x^2+2x^2 + (-8 - 4) = 3x^2 - 12

Hence, the answer is D) 3x^2 - 12.

3 0

3 years ago

Given:

diamong [38]

Answer:

10-5 $\sqrt{2}$

Step-by-step explanation:

As per the attached figure, right angled $\triangle MDL$ has an inscribed circle whose center is $I$ .

We have joined the incenter $I$ to the vertices of the $\triangle MDL$ .

Sides MD and DL are equal because we are given that $\angle M = \angle L = 45 ^\circ.$

Formula for <em>area</em> of a $\triangle = \dfrac{1}{2} \times base \times height$

As per the figure attached, we are given that side <em>a = 10.</em>

Using pythagoras theorem, we can easily calculate that side ML = 10 $\sqrt{2}$

Points P,Q and R are at $90 ^\circ$ on the sides ML, MD and DL respectively so IQ, IR and IP are heights of $\triangle$ MIL, $\triangle$ MID and $\triangle$ DIL.

Also,

$\text {Area of } \triangle MDL = \text {Area of } \triangle MIL +\text {Area of } \triangle MID+ \text {Area of } \triangle DIL$

$\dfrac{1}{2} \times 10 \times 10 = \dfrac{1}{2} \times r \times 10 + \dfrac{1}{2} \times r \times 10 + \dfrac{1}{2} \times r \times 10\sqrt2\\\Rightarrow r = \dfrac {10}{2+\sqrt2} \\\Rightarrow r = \dfrac{5\sqrt2}{\sqrt2+1}\\\text{Multiplying and divinding by }(\sqrt2 +1)\\\Rightarrow r = 10-5\sqrt2$

So, radius of circle = $10-5\sqrt2$

8 0

3 years ago