$(x+2)(x-1)= x^2+2x-x-2= x^2 +x -2\\\\( x + 2 ) ( x - 1 ) - x ^ { 2 } + 1 =x^2+x-2-x^2+1=x-1\\\\- 3 [ ( x + 2 ) ( x - 1 ) - x ^ { 2 } + 1 ] =-3(x-1)=-3x+3\\\\- 3 [ ( x + 2 ) ( x - 1 ) - x ^ { 2 } + 1 ] + 3 ( x - 1 ) =-3x+3+3x-3=6x\\$

5 0

3 years ago

True or False?

almond37 [142]

#1

That is false..one could have side lengths of 9 and 1, and the other could have side lengths of 3. Both the areas would be 9, but the figures would not be congruent.

#2

That is true, they must both have the same side length to have the same perimeter, therefore they will also have the same area.

8 0

3 years ago

A student inscribes a triangle within a semicircle. What is the measure of ∠XYZ?

nata0808 [166]

Answer: a. 90°

Step-by-step explanation:

We know that the in a circle, the measure of an inscribed angle is half the measure of the central angle with the same intercepted arc.

In the problem∠XYZ is the inscribed angle

∠XYZ= $\frac{1}{2}\ arc(XZ)$