For 13 a 0 degree line is a straight line
Angle AOC = 46° Find angle BPO
We have congruent right triangles PAO and PBO, right angles A and B.
So AOC=BOC=46 degrees,
PBO is a right angle so BPO is complementary to BOC, so 42 degrees
Answer: 42 degrees
If in the triangle ABC , BF is an angle bisector and ∠ABF=41° then angle m∠BCE=8°.
Given that m∠ABF=41° and BF is an angle bisector.
We are required to find the angle m∠BCE if BF is an angle bisector.
Angle bisector basically divides an angle into two parts.
If BF is an angle bisector then ∠ABF=∠FBC by assuming that the angle is divided into two parts.
In this way ∠ABC=2*∠ABF
∠ABC=2*41
=82°
In ΔECB we got that ∠CEB=90° and ∠ABC=82° and we have to find ∠BCE.
∠BCE+∠CEB+EBC=180 (Sum of all the angles in a triangle is 180°)
∠BCE+90+82=180
∠BCE=180-172
∠BCE=8°
Hence if BF is an angle bisector then angle m∠BCE=8°.
Learn more about angles at brainly.com/question/25716982
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No idea sorry! If I knew I would tell you
Answer:
a.
the function we are working with
Step-by-step explanation:
f(x) is functions notation which means the output for the function being worked with. It is the y value hence y=f(x).
