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Digiron [165]
3 years ago
9

2. If 5 + x = 12, and you add-5 to the left side of equation, what should you add to the right side of the equation?

Mathematics
2 answers:
Dafna1 [17]3 years ago
8 0

Answer:

b.-5

Step-by-step explanation:

Whatever you do to one side you do to the other

Dennis_Churaev [7]3 years ago
6 0

Answer:

b. -5

Step-by-step explanation:

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111010

Step-by-step explanation:

it is the correct answer

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What is the value of x<br>1. 124<br>2. 62<br>3. 112<br>4. 68<br>explain why the answer is correct ​
Fynjy0 [20]

Answer:

<h2>3.112<em> </em><em>because</em><em> </em><em>5</em><em>6</em><em>+</em><em>5</em><em>6</em><em>=</em><em>1</em><em>1</em><em>2</em></h2>
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I need help with this problem, if anyone could help ASAP, that would be much appreciated. In the figure below, mROP = 125° Find
VARVARA [1.3K]

Answer:

mRP = 125°

mQS = 125°

mPQR = 235°

mRPQ = 305°

Step-by-step explanation:

Given that

  • mROP = 125°
  • ∠ROP is a central angle

Then:

  • measure of arc RP, mRP = mROP = 125°

Given that

  • ∠QOS and ∠ROP are vertical angles

Then:

  • mQOS = mROP = 125°
  • measure of arc QS, mQS = mROP = 125°

Given that

  • ∠QOR and ∠SOP are vertical angles

Then:

  • mQOR = mSOP

Given that

  • The addition of all central angles of a circle is 360°

Then:

mQOS + mROP + mQOR + mSOP = 360°

250° + 2mQOR = 360°

mQOR = (360°- 250°)/2

mQOR = mSOP = 55°

And (QOR and SOP are central angles):

  • measure of arc QR, mQR = mQOR = 55°
  • measure of arc SP, mSP = mSOP = 55°

Finally:

measure of arc PQR, mPQR = mQOR + mSOP + mQOS = 55° + 55° + 125° = 235°

measure of arc RPQ, mRPQ = mROP + mSOP + mQOS = 125° + 55° + 125° = 305°

6 0
3 years ago
Expresion 2 5+4X2+6-2X2-1 Insert parentheses in Expression 2 so that it has a value of 19. Then show why your expression has a v
solong [7]
(5+4+6-2)×2×2-1
(9-4)×2×2-1
5×2×2--1
10×2-1
20-1
19
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3 years ago
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