Answer:
(0, 2) and (2, -6), among other points!
Step-by-step explanation:
If all you need is two points, choose two values for x and plug them into the formula for the function.
so the point (0, 2) is on the graph.
so the point (2, -6) is on the graph.
using the law of cosines:
a^2 = b^2 + c^2 - 2*b*c*cos(A)
a = 90, b = 55, c = 50
90^2 = 55^2 + 50^2 - 2*55*50*cos(A)
8100 = 3025 + 2500 - 5500 * cos(A)
5500 * cos(A) = 3025 + 2500 - 8100
5500 * cos(A) = -2575
cos(A) = -103/220
A = arccos(-103/220)
A = 117.9 degrees
(21 3/4) / (2 1/2) =
(87/4) / (5/2) =
87/4 * 2/5 =
174/20 reduces to 8 7/10 (or 8.7)meters per hr
F(x)=(x-8)/(x+7). g(x)=(-7x-8)/(x-1). Plug in g(x) into f(x), f(g(x))=[(-7x-8)/(x-1)-8]/[-7x-8)/(x-1)+7], which can be simplified as (-7x-8-8x+8)/(-7x-8+7x-7)=-15x/-15=x. Plug in f(x) into g(x), g(f(x))=[-7*(x-8)/(x+7)-8]/[(x-8)/(x+7)-1]=(-7x+56-8x-56)/(x-8-x-7)=-15x/-15=x, as desired.
Answer:
1408
Step-by-step explanation:
