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fredd [130]
3 years ago
12

Explain why domain restrictions for inverse trigonometric functions are necessary​

Mathematics
1 answer:
luda_lava [24]3 years ago
8 0

ANSWER

The domain of the trigonometric functions must be restricted in order to become invertible.

EXPLANATION

Trigonometric functions are periodic functions.

This functions are not invertible over the entire domain of the real numbers because they fail the horizontal line test.

However if we restrict the domain of trigonometric functions, they will now pass the horizontal line test and hence become invertible.

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I have a square graph, but I would like to make the graph larger.
fenix001 [56]

FORMULA:

  • Area of ⬜ = (side)²

ANSWER:

We are given new side of square i.e, 2s + 3.

So, Area = (2s + 3)²

  • (2s)² + (3)² + 2 × 2s × 3
  • 4s² + 9 + 12s

Hence, The area of the new graph is a perfect square trinomial: __4__s² + __12__s +__9__.

4 0
3 years ago
Solve for x:<br> -1/3(4x+2)=1/3(x+11)<br><br> A. -13/3<br> B. -3<br> C. -13/5<br> D. -9/5
Nataly_w [17]
X=-13/5

Simplify both sides of the equation, isolate the variable, and then you get your answer. 
7 0
3 years ago
I was wondering what is the best math to take after Algebra 2
Elan Coil [88]
The best math that i think you should take would be calculus.
7 0
2 years ago
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Li is tracking the amount in his bank account. He now has $125, and he plans to deposit $45 each month. In how many months will
UkoKoshka [18]
(1 month) 125+45=170
(2 month) 170+45=215
(3 month) 215+45= 260
(4 month) 260+45=305
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Li needs at least $360 in get account which means 5 months would not work because it is less than $360.
So, add one more $45 and get $395 which is more than enough money for Li.

Overall, Li would need 6 months to get at least $360 in her bank account.

I hope this helps!!
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3 years ago
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Maria wrote the equation log(x/2)+log(20/x^2)=log8. What is the solution to Maria's equation?
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The solution is x=5/4.

We use the properties of logs to rewrite the equation:
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Get all of the logs on the same side of the equation y subtracting log 8:
\log(\frac{10}{x})-\log8=\log8 - \log8&#10;\\&#10;\\\log(\frac{10}{x})-\log8=0

Use the properties of logs to rewrite:
\log(\frac{10}{x}\div8)=0&#10;\\&#10;\\\log(\frac{10}{x}\div\frac{8}{1})=0&#10;\\&#10;\\\log(\frac{10}{x}\times\frac{1}{8})=0&#10;\\&#10;\\\log(\frac{10}{8x})=0

Exponentiate:
10^0=\frac{10}{8x}&#10;\\&#10;\\1=\frac{10}{8x}

Multiply both sides by 8x:
1*8x = (10/8x)*8x
8x=10

Divide both sides by 8:
8x/8 = 10/8
x = 10/8 = 5/4
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3 years ago
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