How do I find the average number of particles hitting the surface poer unit area and per unit time with no information?
Answer:
D
Step-by-step explanation:
The starting point is B and the ray extends towards A.
So the asnwer is D.
Answer:
a)$15.95
b) 8kg
Step-by-step explanation:
a)Approach this question by finding how much does it cost for 1g
So,
$2.1/50=$0.042per gram
then, multiple 380 to get the cost of sweets for 380 g
$0.042/gram*380gram=$15.96(Note: the gram cancel out each other)
Which is $15.95 as the question requested
b)This question stated that 3/4 of the metal has 15 kg
So, in order to find the total mass of metal we invert the 3/4 fraction
e.g 4/3*15=20kg
now we have the total mass we can find the mass for 2/5 of the metal
2/5*20kg=8kg
The expression you want to simplify is 0-(x-y).
0-(x-y)
=-(x-y)
=-x+y
You just have to treat the negative sign in front of (x-y) as a -1 and distribute it to both x and -y.
Answer:
-499,485.
Step-by-step explanation:
We can transform this to an arithmetic series by working it out in pairs:
6^2 - 7^2 = (6-7)(6+7) = -13
8^2 - 9^2 = (8-9)*8+9) = -17
10^2 - 11^2 = -1 * 21 = -21 and so on
The common difference is -4.
The number of terms in this series is (998 - 6) / 2 + 1
= 992/2 + 1 = 497.
Sum of n terms of an A.S:
= n/2 [2a1 + (n - 1)d
Here a1 = -13, n = 497, d = -4:
Sum = (497/2)[-26 - 4(497-1)]
= 497/2 * -2010
= -499,485.
