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enot [183]
3 years ago
9

The base of a cube is parallel to the horizon. If the cube is cut by a plane to form a cross section, under what circumstance ca

n the cross section be a non-rectangular parallelogram?
when the plane cuts three faces of the cube, separating one corner from the others

when the plane passes through a pair of vertices that do not share a common face


when the plane is perpendicular to the base and intersects two adjacent vertical faces


when the plane makes an acute angle to the base and intersects three vertical faces


not enough information to answer the question
Mathematics
2 answers:
Nikolay [14]3 years ago
7 0
Based on the given question above, the correct answer would be the fourth option. The <span>circumstance that the cross section can be a non-rectangular parallelogram is that, </span><span>when the plane makes an acute angle to the base and intersects three vertical faces. Hope this answers the question. </span>
Vaselesa [24]3 years ago
3 0

Answer:

the fourth option

Step-by-step explanation:

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3) When mixing a paint color, you need to use 2 gallons of white and 3 gallons of blue. How many gallons of
elixir [45]

Answer:

I think the answer is 25

Step-by-step explanation:

So, if you add 2 and 3, you get 5.

Multiply 5 by 10 to get 50

Divide 50 by 2 to get 25

So, you'll need 25 gallons of paint.

Hope this helped!

(Please mark as Brainliest <3)

6 0
3 years ago
1. Point P is between points F and G. The distance between points F and P
Ivenika [448]

Answer:

Point P is in between points F and G.

Now, here we do not have the actual locations of F and G, so i will answer this in a general way.

Suppose that F is located at 0 and G is located at some value A.

Then the distance FG = A - 0 = A.

Now, the distance between F and P is:

Distance  = (1/4)*FG = A/4

Then the location of P is equal to the location of F plus A/4

P = 0 + A/4

Now, writing this in a more general way:

P = F + FG/4

8 0
3 years ago
PLease solve for n I dont know how to do it
rewona [7]

Answer:

37

Step-by-step explanation:

6 0
3 years ago
How do i solve this?
Ahat [919]
In terms of p, the answer is p= -q-3

8 0
3 years ago
Read 2 more answers
Graph triangle RST with vertices R(3, 7), S(-5, -2), and T(3, -5) and its image after a reflection over x = -3.​
kirill115 [55]

Given:

The vertices of a triangle are R(3, 7), S(-5, -2), and T(3, -5).

To find:

The vertices of the triangle after a reflection over x = -3 and plot the triangle and its image on the graph.

Solution:

If a figure reflected across the line x=a, then

(x,y)\to (-(x-a)+a,y)

(x,y)\to (-x+a+a,y)

(x,y)\to (2a-x,y)

The triangle after a reflection over x = -3. So, the rule of reflection is

(x,y)\to (2(-3)-x,y)

(x,y)\to (-6-x,y)

The vertices of triangle after reflection are

R(3,7)\to R'(-6-3,7)

R(3,7)\to R'(-9,7)

Similarly,

S(-5,-2)\to S'(-6-(-5),-2)

S(-5,-2)\to S'(-6+5,-2)

S(-5,-2)\to S'(-1,-2)

And,

T(3,-5)\to T'(-6-3,-5)

T(3,-5)\to T'(-9,-5)

Therefore, the vertices of triangle after reflection over x=-3 are R'(-9,7), S'(-1,-2) and T'(-3,-5).

3 0
3 years ago
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