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il63 [147K]
2 years ago
7

Find the interquartile range of the data represented by this box plot.

Mathematics
2 answers:
Eduardwww [97]2 years ago
7 0

Answer:

B) 30

Step-by-step explanation:

The interquartile range in 100 to 130.

130-100=30

erma4kov [3.2K]2 years ago
7 0

Answer:

what school is this idk lol

B30

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Samuel consumed 2161 calories of food on​ Monday, 2378 calories on​ Tuesday, and 1841 calories on Wednesday. In order for​ Samue
german
Number of calories consumed on Monday = 2161
Number of Calories consumed on Tuesday = 2378
Number of Calories consumed on Wednesday = 1841
Daily average intake is 2200
Let calories intake on Thursday be X

Now ,

Average = sum of total calories/ number of calories

=> 2200 = 2161+2378+1841+X/4

=> 2200 x 4 = 6377 + X

=> 8800 = 6377 + X

=> X = 8800-6377

=> X = 2423

So Samuel must consume 2423 calories on Thursday
3 0
2 years ago
The equation of line l is -3y + 4x = 9 . Write the equation of a line that is parallel to line l and passes through the point (-
Elan Coil [88]

Answer: y = 3x/4 + 22

Step-by-step explanation:

The equation of line l is -3y + 4x = 9

-3y + 4x = 9

3y = 4x -9

y = (4x -9)/3= 4x/3 - 3

From the slope-intercept equation,

y = mx +c

Where m= slope

Comparing both equations, we have

m = 4/3

If the new line that parallel to line l, that means they have the same slope

So, slope if new line is 3/4.

Points =(-12, 6)

From y = mx + c

x = -12,y = 6

6= 4/3 × -12 + c

6 = -16 + c

c = 6 + 16 = 22

Therefore

The equation of the line that is parallel to line l and passes through the point (-12,6) ,

y = 3x/4 + 22

7 0
3 years ago
No entendi lpM explicen
LuckyWell [14K]
No able engles? Don’t know if i spelt that right but
3 0
3 years ago
Need help math problem give you 5 stars and a good rating if you do this
Mazyrski [523]

Answer:

Add 9.6 then divide by 3.2

8 0
2 years ago
The choices are <br> X &lt; -6<br> X &gt; -6<br> X&lt;_ -6<br> X&gt; -6
elena-14-01-66 [18.8K]
  • Starting point of arrow is -6.
  • The arrow is travelling to wards left.
  • I.e the arrow is decreasing and x is decreasing.

Hence the solution is

\\ \tt\hookrightarrow x\in (-\infty,-6]

  • x<=-6
5 0
2 years ago
Read 2 more answers
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