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il63 [147K]
3 years ago
7

Find the interquartile range of the data represented by this box plot.

Mathematics
2 answers:
Eduardwww [97]3 years ago
7 0

Answer:

B) 30

Step-by-step explanation:

The interquartile range in 100 to 130.

130-100=30

erma4kov [3.2K]3 years ago
7 0

Answer:

what school is this idk lol

B30

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3 years ago
PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!
sweet-ann [11.9K]

Answer:  $25,500

<u>Step-by-step explanation:</u>

The given sequence {1300, 1300+150, ... } provides the following information:

  • the first term (a₁) = 1300
  • the difference (d) = 150

We can use the information above to find the explicit rule of the sequence:

a_n=a_1+d(n-1)\\.\quad =1300+150(n-1)\\.\quad =1300+150n-150\\.\quad =1150+150n

We can use the explicit rule to find the 12th term (a₁₂)

a_n=1150+150n\\a_{12}=1150+150(12)\\.\quad =1150+1800\\.\quad =2950

Next, we can input the first and last term of the sequence into the Sum formula:

S_n=\dfrac{a_1+a_n}{2}\times n\\\\S_{12}=\dfrac{a_1+a_{12}}{2}\times 12\\\\.\quad =\dfrac{1300+2950}{2}\times 12\\\\.\quad =\dfrac{4250}{2}\times 12\\\\.\quad =2125\times 12\\\\.\quad =25,500

3 0
3 years ago
Read 2 more answers
Let f(x) = [infinity] xn n2 n = 1 . Find the intervals of convergence for f. (Enter your answers using interval notation.) Incor
sveta [45]

Answer:

The interval of convergence is -1<x<1

Step-by-step explanation:

To find the interval of convergence of the series, we will use the condition for convergence of a series according to Ratio test.

The solution is as shown in the attachment.

7 0
3 years ago
Incase you can’t see the picture, it says “Explain how to solve the following equation and check for extraneous solutions: x= sq
Alex_Xolod [135]

Answer:

x=3

Step-by-step explanation: too much math to put here

8 0
3 years ago
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PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!
Molodets [167]
Week 1: $100
Week 2: $102
Week 3: $104.04
Week 4: $106.1208
Week 5: $108.243216
Week 6: $110.40808032
Week 7: $112.6162419264
Week 8: $114.868566764928
Total: $858.296905011328

(A=100[((1+0.02)^(8)-1)(/0.2)=858.29

Hope that helped!
5 0
4 years ago
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