D(1/x)/dx= d(x^-1)/dx
= -x^-2
the derivatives of the two cases you mentioned is as follows:
(I) f(x)=k/x
d{f(x)}/dx= k×(-x^-2)
= -kx^-2
(ll) f(x)=x/k
d{f(x)}= d(x/k)/dx
= 1/k
you can just simply take out the constant from the derivative and multiply it to the final answer of the derivative of the given function.
You need to know the cost per ounce, or how many cents per one ounce, and the best buy is the 14-ounce bottle.
Answer:
D
Step-by-step explanation:
Answer:
Step-by-step explanation:
First simplify:
Therefore we have:
![\sum\limits_{n=1}^{150}[-1-(n-1)]=\sum\limits_{n=1}^{150}(-n)=(-1)+(-2)+(-3)+...+(-150)\\\\-1,\ -2,\ -3,\ -4,\ ...,\ -150-\text{it's the arithmetic sequence}\\\text{with the common difference d = -1.}\\\\\text{The formula of a sum of terms of an arithmetic sequence:}\\\\S_n=\dfrac{a_1+a_n}{2}\cdot n\\\\\text{Substitute}\ n=150,\ a_1=-1,\ a_n=-150:\\\\S_{150}=\dfrac{-1+(-150)}{2}\cdot150=(-151)(75)=-11,325](https://tex.z-dn.net/?f=%5Csum%5Climits_%7Bn%3D1%7D%5E%7B150%7D%5B-1-%28n-1%29%5D%3D%5Csum%5Climits_%7Bn%3D1%7D%5E%7B150%7D%28-n%29%3D%28-1%29%2B%28-2%29%2B%28-3%29%2B...%2B%28-150%29%5C%5C%5C%5C-1%2C%5C%20-2%2C%5C%20-3%2C%5C%20-4%2C%5C%20...%2C%5C%20-150-%5Ctext%7Bit%27s%20the%20arithmetic%20sequence%7D%5C%5C%5Ctext%7Bwith%20the%20common%20difference%20d%20%3D%20-1.%7D%5C%5C%5C%5C%5Ctext%7BThe%20formula%20of%20a%20sum%20of%20terms%20of%20an%20arithmetic%20sequence%3A%7D%5C%5C%5C%5CS_n%3D%5Cdfrac%7Ba_1%2Ba_n%7D%7B2%7D%5Ccdot%20n%5C%5C%5C%5C%5Ctext%7BSubstitute%7D%5C%20n%3D150%2C%5C%20a_1%3D-1%2C%5C%20a_n%3D-150%3A%5C%5C%5C%5CS_%7B150%7D%3D%5Cdfrac%7B-1%2B%28-150%29%7D%7B2%7D%5Ccdot150%3D%28-151%29%2875%29%3D-11%2C325)
7/8 < 9/10
thats the answer
Hope this Helped :D
