Question

Half of Robert's piece of wire is equal to 2 thirds of Maria's wire. The total length of their wires is 10 feet. How much longer is Robert's wire than Maria's wire?

Answer 1

Answer:

let x be the Robert piece

y Maria's piece

x+y=10

0,5*x ( half of Robert piece)= 2/3 y( 2 thirds)

2 equations then

x+y= 10 then x= 10-y

0,5x= 0,67 y  then we replace x by 10-y on the second equation and it gives

0,5(10-y)= 5-0,5y=0,67y

5= 1,17 y so y= 4,27    and then x= 10-y= 5,73

the question asks how much Robert wire is longer than Maria's wire

so we get x-y= 1,46

Answer 2

Robert's wire is longer $\frac{4}{3}$ times than Maria's wire and also   it $\frac{10}{7}$ longer than Maria's wire

Further explanation

A wire is a single, usually cylindrical, flexible strand or rod of metal. It are used to bear mechanical loads or electricity and telecommunications signals.  

Half of Robert's wire = 2 thirds of Maria's wire, so

$\frac{1}{2} *$  Robert's wire = $\frac{2}{3} * Maria's wire$

The total length of their wires = 10 feet

10 feet =  Robert's wire + Maria's wire

10 feet =  $\frac{4}{3} * Maria's wire$ + Maria's wire

10 feet =  $\frac{7}{3} * Maria's wire$

Maria's wire =  $\frac{30}{7}$  feet

 $\frac{1}{2} *$   Robert's wire = $\frac{2}{3} * Maria's wire$

Robert's wire = $\frac{4}{3} * \frac{30}{7}$

Robert's wire =  $\frac{120}{21} feet$

Robert's wire = $\frac{40}{7} feet$

If we draw the piece, we get the information that

7 units = 10 feet

1 unit = $\frac{10}{7}$ feet

Hence the  Robert's wire is $\frac{10}{7}$ longer than Maria's wire because

Robert's wire - Maria's wire =   $\frac{40}{7} - \frac{30}{7} feet = \frac{10}{7} feet$

Learn more

1. Learn more about wire brainly.com/question/9917316
2. Learn more about feet brainly.com/question/9197825
3. Learn more about  piece of wire brainly.com/question/2765322

Answer details

Grade:  5

Subject:  math

Chapter:  wire

Keywords:  

wire, feet,  piece of wire, piece, wires