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3 years ago

Which factor contributed most to the decline of the buffalo population in the West in the late 1800s?

2 answers:

6 0

Manifest destiny, as many settlers moved west after the Louisiana purchase to claim land that the U.s government was handing out. With a sudden influx of settlers and people needing to eat/make money off of their pelts. The buffalo population declined

lbvjy [14]3 years ago

6 0

Answer:

if your on study the answer is

C. over-hunting

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Anna is making 11 necklaces using 35 beads for each. How many beads (B) are needed to make all of the necklaces?

Fed [463]

Answer:

B/35=11

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

find the surface area of a right regular hexagonal pyramid with sides 3 cm and slant heights 6cm. show all of your work.

DedPeter [7]

Answer:

The surface area of right regular hexagonal pyramid = 82.222 cm³

Step-by-step explanation:

Given as , for regular hexagonal pyramid :

The of base side = 3 cm

The slant heights = 6 cm

Now ,

The surface area of right regular hexagonal pyramid = $\frac{3\sqrt{3}}{2}\times a^{2} + 3 a \sqrt{h^{2}+ 3\times \frac{a^{2}}{4}}$

Where a is the base side

And h is the slant height

So, The surface area of right regular hexagonal pyramid = $\frac{3\sqrt{3}}{2}\times 3^{2} + 3 \times 3 \sqrt{6^{2}+ 3\times \frac{3^{2}}{4}}$

Or, The surface area of right regular hexagonal pyramid = $\frac{3\sqrt{3}}{2}\times 9 + 9 \sqrt{36+ 3\times \frac{9}{4}}$

Or, The surface area of right regular hexagonal pyramid = 23.38 + 9 × $\frac{171}{4}$

∴ The surface area of right regular hexagonal pyramid = 23.38 + 9 × 6.538

I.e The surface area of right regular hexagonal pyramid = 23.38 + 58.842

So, The surface area of right regular hexagonal pyramid = 82.222 cm³ Answer

6 0

3 years ago

Use the four functions below for this question:

Jlenok [28]

Answer:

We have four functions:

For f(x) we have two points (-2,2) and (-1,-1)

we will use two point form which is:

$y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)$

So, on substituting the values we get:

$y-2=\frac{-1-2}{-1-(-2)}(x-(-2))$

$y-2=\frac{-3}{x+2}$

$y=-3x-4$

So, f(x)=-3x-4

We have g(x)=3x-4

Now, we will from h(x) we have two points let initial point on monday is (0,4) and tuesday (1,1) again use two point form we get:

$y-4=-3(x-0)$

$\Rightarrow y=-3x+4$

So, h(x)= -3x+4

Now, we will form j(x) we have three points (2,10) , (-2,6) and (2,22)

We will use (-2,6) and (2,22) to find the function with two point form.

$y-6=\frac{22-6}{2+2}x+2)$

$\Rightarrow y=4x+14$

j(x)= 4x+14

To find the slope we will compare the given function with general equation which is y= mx +c; m is the slope

And to find y-intercept we will put x=0

f(x)=-3x-4

Slope is: -3

And y-intercept is: (0,-4)

g(x)=3x-4

Slope is: 3

And y-intercept is: (0,-4)

h(x)= -3x+4

Slope is: -3

And y-intercept is: (0,4)

j(x)= 4x+14

Slope is: 4

And y-intercept is: (0,14)

8 0

3 years ago

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Find the area and perimeter the Gym, Cafeteria, and Locker

Serjik [45]

Answer:

Gym: A=100 P=41

Cafeteria: A=144 P=48

Locker room: A=75 P= 37

3 0

3 years ago

Moreeeeee points. Hope you guys like

Xelga [282]

Answer:

Thank you very much :3

Have a great day!

also 1 + 1 is 2

4 0

2 years ago

Read 2 more answers