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GaryK [48]
3 years ago
14

What is the product of? (7x^2)(2x^3+5)(x^2-4x-9)

Mathematics
2 answers:
pav-90 [236]3 years ago
6 0
(7x^{2})(2x^{3} +5)( x^{2} -4x-9)

(14 x^{5} +35 x^{2})( x^{2} -4x-9)
=14 x^{7} -56 x^{6}-126 x^{5}+35 x^{4}-140 x^{3}-315 x^{2}
devlian [24]3 years ago
5 0

Answer:

14x^7 -56x^6-126x^5+35x^4-140x^3-315x^2

Step-by-step explanation:

(7x^2)(2x^3+5)(x^2-4x-9)

Find the product of (7x^2)(2x^3+5)(x^2-4x-9)

Multiply the parenthesis

(7x^2)(2x^3+5)=14x^5+35x^2

Now we multiply 14x^5+35x^2 inside last parenthesis

( 14x^5+35x^2)(x^2-4x-9)

14x^7 -56x^6-126x^5+35x^4-140x^3-315x^2

Combine like terms if any

14x^7 -56x^6-126x^5+35x^4-140x^3-315x^2

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6.5x+1.5<21

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