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Nikitich [7]
4 years ago
13

A landscaper is designing a rectangular garden. The length of the garden is to be 5 feet longer than the width. If the area of t

he garden will be 104 square feet, what will be the length, in feet, of the garden?
Mathematics
2 answers:
Vesna [10]4 years ago
7 0

Answer:

13 feet

Step-by-step explanation:

Let x be the width of the rectangular garden.

We are given that the length of the garden is to be 5 feet longer than the width.

So, Length = x+5

Area of rectangle = Length \times Width

                             = x \times (x+5)

We are given that the area of the garden will be 104 square feet

So, x \times (x+5)=104

x^2+5x -104=0

(x-8)(x+13)=0

x=8,-13

Since the width cannot be negative.

So, neglect -13

So, width = x = 8

Length = x+5 = 8+5 = 13

So, the length of the garden is 13 feet.

Dmitry [639]4 years ago
4 0
Width = y
length = y+5
area = 104 = y x (y+5) = y^2 + 5y
y^2 + 5y -104 = 0
(y-8)(y+13)= 0
y= 8 because can't have negative lengths
length = 8 + 5 = 13
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Remark

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