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Maksim231197 [3]
3 years ago
11

Help with 1 and 3 if possible show work

Mathematics
1 answer:
Vinvika [58]3 years ago
5 0
1)

\bf \qquad \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+r\right)^{t}
\quad 
\begin{cases}
A=\textit{compounded amount}\\
P=\textit{original amount deposited}\to &\$600\\
r=rate\to 1.6\%\to \frac{1.6}{100}\to &0.016\\
t=years\to &2
\end{cases}
\\\\\\
A=600\left(1+0.016\right)^{2}

3)

\bf V(t)=1350(1.017)^t\implies 
\begin{array}{llllll}
V(t)&=&1350(&1 +& 0.017&)^t\\
A&=&P(&1+&\boxed{r}&)^t
\end{array}

notice the rate "r"... now, is in decimal format, as you saw on 1) is just r/100 so 1.6% was really 1.6/100 or 0.016  anyhow

to get the percentage form, just multiply it by 100

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Limit of x^2-81/x+9<br> As x goes toward -9
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Hello,

Use the factoration

a^2 - b^2 = (a - b)(a + b)

Then,

x^2 - 81 = x^2 - 9^2

x^2 - 9^2 = ( x - 9).(x + 9)

Then,

Lim (x^2- 81) /(x+9)

= Lim (x -9)(x+9)/(x+9)

Simplity x + 9

Lim (x -9)

Now replace x = -9

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The second method without using factorization would be to calculate the limit by the hospital rule.

Lim f(x)/g(x) = lim f(x)'/g(x)'

Where,

f(x)' and g(x)' are the derivates.

Let f(x) = x^2 -81

f(x)' = 2x + 0
f(x)' = 2x

Let g(x) = x +9

g(x)' = 1 + 0
g(x)' = 1

Then the Lim stay:

Lim (x^2 -81)/(x+9) = Lim 2x /1

Now replace x = -9

Lim 2×-9 = Lim -18

= -18




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Attached is a screenshot.

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