Help with 1 and 3 if possible show work

Mathematics

1 answer:

Vinvika [58]3 years ago

5 0

1)

$\bf \qquad \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+r\right)^{t}
\quad 
\begin{cases}
A=\textit{compounded amount}\\
P=\textit{original amount deposited}\to &\$600\\
r=rate\to 1.6\%\to \frac{1.6}{100}\to &0.016\\
t=years\to &2
\end{cases}
\\\\\\
A=600\left(1+0.016\right)^{2}$

3)

$\bf V(t)=1350(1.017)^t\implies 
\begin{array}{llllll}
V(t)&=&1350(&1 +& 0.017&)^t\\
A&=&P(&1+&\boxed{r}&)^t
\end{array}$

notice the rate "r"... now, is in decimal format, as you saw on 1) is just r/100 so 1.6% was really 1.6/100 or 0.016 anyhow

to get the percentage form, just multiply it by 100

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In the diagram below, what is the equation that represents the relationship between the number of triangles and the perimeter of

Marina86 [1]

Answer:

The perimeter of the figure as a function of the number of triangles is $y = 6 + 4\cdot x$ .

Step-by-step explanation:

According to the diagram, we get the following facts:

i) For one triangle ( $x=1$ ), the total perimeter is ( $y=2\cdot 3 + 1\cdot 4 = 10$ ).

ii) For two triangles ( $x = 2$ ), the total perimeter is ( $y = 2\cdot 3 +2\cdot 4 = 14$ )

iii) For three triangles ( $x = 3$ ), the total perimeter is ( $y = 2\cdot 3 +3\cdot 4 = 18$ )

iv) For four triangles ( $x = 4$ ), the total perimeter is ( $y = 2\cdot 3 +4\cdot 4 = 22$ )

From these information we conclude that the equation that determines the perimeter of the figure as a function of the number of triangles is $y = 6 + 4\cdot x$ .

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How many phone numbers are possible for one area code if the first four numbers are 202-1 , in that order , and the last three n

Mkey [24]

6 phone numbers are possible for one area code if the first four numbers are 202-1

<u>Solution:</u>

Given that, the first four numbers are 202-1, in that order, and the last three numbers are 1-7-8 in any order

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The number of way “n” objects can be arranged is given as n!

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