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Bond [772]
3 years ago
11

A right cylinder has a volume of 2000 cubic inches and a height of 4 inches. What is the radius of the cylinder to the nearest t

enth of an inch
Mathematics
1 answer:
Akimi4 [234]3 years ago
3 0

Explanation at the top answer at the bottom

V=B*h
The height equals to 4
Volume equals to 200

Let's plug it in
2000=B*4
B*4=2000
This means something multiplied times 4 equals 2000
4/2000=500
500*4=2000
B=500 the base of a cylinder is a circle and that base includes our radius

so now we know that the Base of a cylinder is equal to 500

Area of circle = 500
The formula for area of a circle is 3.14*r^2
let's plug everything in
3.14*r^2=500
r^2=496.9
22.23^2=496. Approximately

Radius equals to

R=22.2

Please consider up voting it took me sometime to find your answer. Let me know if you need anymore help.
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Answer:

The roots are x = (\frac{3}{2}, -2), which is given by option C.

Step-by-step explanation:

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

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This polynomial has roots x_{1}, x_{2} such that ax^{2} + bx + c = a(x - x_{1})*(x - x_{2}), given by the following formulas:

x_{1} = \frac{-b + \sqrt{\Delta}}{2*a}

x_{2} = \frac{-b - \sqrt{\Delta}}{2*a}

\Delta = b^{2} - 4ac

In this question, we have that:

2x^2 + x - 6 = 0

Which is a quadratic equation with a = 2, b = 1, c = -6. So

\Delta = 1^{2} - 4*2(-6) = 1 + 48 = 49

x_{1} = \frac{-1 + \sqrt{49}}{2*2} = \frac{6}{4} = \frac{3}{2}

x_{2} = \frac{-1 - \sqrt{49}}{2*2} = \frac{-8}{4} = -2

So the roots are x = (\frac{3}{2}, -2), which is given by option C.

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