Answer:
notebook: $2.5
pen: $1.5
part B, he can buy 3 pens
Step-by-step explanation:
A
let the cost of notebook be n, cost of pen be p
1. 4n + 3p = 14.5
2. 5n + 6p = 21.5
by 1, you can get 3p = 14.5 - 4n, put it into 2
5n + 2(14.5 - 4n) = 21.5
5n + 29 - 8n = 21.5
3n = 29 - 21.5 = 7.5
n = 2.5
put n = 2.5 into 1
4(2.5) + 3p = 14.5
3p = 4.5
p = 1.5
B
Waseem buy 3 notebooks for each pen, let number of pen be m, then the number of notebook will be 3m
m(2.5) + 3m(1.5) < 27
2.5m + 4.5m = 7m < 27
m < 27/7
maximum integer value for m = 3
190 = x + 2(x+20)
190 = x + 2x + 40
190 = 3x + 40
190 - 40 = 150
150/3 = 50
x = 50
190 = 50 + 2(50 + 20)
one side of the width (the "short side", as it says) is the barn, so you don't count that because its only asking for the fencing. the length (which would be the long side, which implies that theres only one short side, if that confused you at all) is 20m longer. we figured out that 50m is the width so if both sides are 20m longer, the dimensions of the fencing would be:
50m + 70m + 70m
Answer:
Option D
188.1 ft
Step-by-step explanation:
![Tan \theta=\frac {object}{shadow}](https://tex.z-dn.net/?f=Tan%20%5Ctheta%3D%5Cfrac%20%7Bobject%7D%7Bshadow%7D)
Therefore,
shadow
Substituting
for
and shadow for 100 ft
![Object=Tan 62^{\circ} \times 100=188.0726465 ](https://tex.z-dn.net/?f=Object%3DTan%2062%5E%7B%5Ccirc%7D%20%5Ctimes%20100%3D188.0726465%0A)
![Object \approx 188.1](https://tex.z-dn.net/?f=Object%20%5Capprox%20188.1)
Answer:
56x-38
Step-by-step explanation:
2(8x+9)-8(7-5x)
16x+18
-8(7-5x)
-56+40x
16x+18-56+40x
Add all like terms
56x-38
Answer:
2 1/2
Step-by-step explanation:
5/8 divided by 1/4 is 2 1/2