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DiKsa [7]
3 years ago
6

Emily is buying a retirement home. The purchase price of the house is $114,500.00. She will put 15% down.

Mathematics
1 answer:
pentagon [3]3 years ago
8 0
Her down payment will be
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Refer to the accompanying data set of mean​ drive-through service times at dinner in seconds at two fast food restaurants. const
Anton [14]

Step-by-step explanation:

Assuming the data is as shown, restaurant X has a mean service time of 180.56, with a standard deviation of 62.6.

The standard error is SE = s/√n = 62.6/√50 = 8.85.

At 95% confidence, the critical value is z = 1.960.

Therefore, the confidence interval is:

180.56 ± 1.960 × 8.85

180.56 ± 17.35

(163, 198)

Restaurant Y has a mean service time of 152.96, with a standard deviation of 49.2.

The standard error is SE = s/√n = 49.2/√50 = 6.96.

At 95% confidence, the critical value is z = 1.960.

Therefore, the confidence interval is:

152.96 ± 1.960 × 6.96

152.96 ± 13.64

(139, 167)

4 0
3 years ago
Doug regularly mows his neighbor's lawn. Last month, Doug's neighbor paid him $55 for 6 hours of mowing. Is this situation most
nasty-shy [4]

Solution:

we are given that

Last month, Doug's neighbor paid him $55 for 6 hours of mowing.

we have been asked that

Is this situation most likely a proportional relationship?

yes..its as proportional relationship.

Because the amount that Doug get is $55 for 6 hours

It mean for each hour Doug get  is \frac{55}{6} $

It mean if you increase the number of hours then the number of dollars get paid also increases. Hence the given  situation is most likely a proportional relationship.



8 0
3 years ago
Show that ( 2xy4 + 1/ (x + y2) ) dx + ( 4x2 y3 + 2y/ (x + y2) ) dy = 0 is exact, and find the solution. Find c if y(1) = 2.
fredd [130]

\dfrac{\partial\left(2xy^4+\frac1{x+y^2}\right)}{\partial y}=8xy^3-\dfrac{2y}{(x+y^2)^2}

\dfrac{\partial\left(4x^2y^3+\frac{2y}{x+y^2}\right)}{\partial x}=8xy^3-\dfrac{2y}{(x+y^2)^2}

so the ODE is indeed exact and there is a solution of the form F(x,y)=C. We have

\dfrac{\partial F}{\partial x}=2xy^4+\dfrac1{x+y^2}\implies F(x,y)=x^2y^4+\ln(x+y^2)+f(y)

\dfrac{\partial F}{\partial y}=4x^2y^3+\dfrac{2y}{x+y^2}=4x^2y^3+\dfrac{2y}{x+y^2}+f'(y)

f'(y)=0\implies f(y)=C

\implies F(x,y)=x^2y^3+\ln(x+y^2)=C

With y(1)=2, we have

8+\ln9=C

so

\boxed{x^2y^3+\ln(x+y^2)=8+\ln9}

8 0
2 years ago
Carl. put $1.10 in his piggy bank every day in the month of July. His total savings was $55 at the end of June. hat is the best
Crank
Carl would have around $90 at the end of July
8 0
3 years ago
Read 2 more answers
A group fitness gym classifies its fitness class attendees by class type and member status. The marketing team has gathered data
PilotLPTM [1.2K]

The probability that a class attendee is a non-member of the gym and is attending a barre class or is a member of the gym and is attending a boot camp class is 0.009.

<h3>What is the probability?</h3>

Probability refers to a possibility that deals with the occurrence of random events.

The marketing team has gathered data from a random month, in which there were 2039 class attendees.

The probability that a class attendee is a non-member of the gym and is attending a barre class

= 185/2039

= 0.09

The probability that a class attendee is a member of the gym and is attending a boot camp class

= 204/2039

= 0.10004

The probability for both the event would be

= 0.09 x 0.10004

= 0.009

Learn more about probability here;

brainly.com/question/11234923

#SPJ1

8 0
2 years ago
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