Step-by-step explanation:
Assuming the data is as shown, restaurant X has a mean service time of 180.56, with a standard deviation of 62.6.
The standard error is SE = s/√n = 62.6/√50 = 8.85.
At 95% confidence, the critical value is z = 1.960.
Therefore, the confidence interval is:
180.56 ± 1.960 × 8.85
180.56 ± 17.35
(163, 198)
Restaurant Y has a mean service time of 152.96, with a standard deviation of 49.2.
The standard error is SE = s/√n = 49.2/√50 = 6.96.
At 95% confidence, the critical value is z = 1.960.
Therefore, the confidence interval is:
152.96 ± 1.960 × 6.96
152.96 ± 13.64
(139, 167)
Solution:
we are given that
Last month, Doug's neighbor paid him $55 for 6 hours of mowing.
we have been asked that
Is this situation most likely a proportional relationship?
yes..its as proportional relationship.
Because the amount that Doug get is $55 for 6 hours
It mean for each hour Doug get is
$
It mean if you increase the number of hours then the number of dollars get paid also increases. Hence the given situation is most likely a proportional relationship.


so the ODE is indeed exact and there is a solution of the form
. We have




With
, we have

so

The probability that a class attendee is a non-member of the gym and is attending a barre class or is a member of the gym and is attending a boot camp class is 0.009.
<h3>What is the probability?</h3>
Probability refers to a possibility that deals with the occurrence of random events.
The marketing team has gathered data from a random month, in which there were 2039 class attendees.
The probability that a class attendee is a non-member of the gym and is attending a barre class
= 185/2039
= 0.09
The probability that a class attendee is a member of the gym and is attending a boot camp class
= 204/2039
= 0.10004
The probability for both the event would be
= 0.09 x 0.10004
= 0.009
Learn more about probability here;
brainly.com/question/11234923
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