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Cloud [144]
2 years ago
8

In a right triangle, cosine a = 0.352 and sine a = 0.936. what is the approximate value of tangent a? 0.329 0.376 1.288 2.659

Mathematics
1 answer:
Flura [38]2 years ago
4 0

The value of tangent a in the right triangle in which , cosine a = 0.352 and sine a = 0.936 is 2.659.

<h3>What are the trigonometric ratios?</h3>

Trigonometric ratios for a right angled triangle are from the perspective of a particular non-right angle. The value of tangent of angle is equal to the ratio of sine of that angle to the cosine of that angle.

\tan\theta=\dfrac{\sin\theta}{\cos\theta}

Here, θ is the angle.

The value of angle given in the problem are,

  • Cosine a = 0.352
  • Sine a = 0.936.

Put these values in the above fromula as,

\tan (a)=\dfrac{\sin(a)}{\cos(a)}\\\tan (a)=\dfrac{0.936}{0.352}\\\tan(a)=2.659

Hence, the value of tangent a in the right triangle in which , cosine a = 0.352 and sine a = 0.936 is 2.659.

Learn more about the trigonometric ratios here;

brainly.com/question/24349828

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The graph of y=ax^2+bx+c passes through points (0,5), (1,10), and (2,19). Find a+b+c.
nataly862011 [7]

Answer:   a = 2   b = 3   c = 5  

Literally a+ b+c = 10, but I don't think that's what the question means to ask.

the equation is 2x² +3x + 5

Step-by-step explanation:   Substitute the values of the given coordinates into the formula and use algebra (solve a system of equations by substitution and elimination) to get the values  of a,b & c

y=ax²+bx+c    using  (0,5), (1,10), and (2,19)

5=a(0)²+b(0)+c   becomes 5= 0+0 + c .so we find c = 5

10=a(1)²+b(1)+c    becomes 10 = a + b + c

19=a(2)²+b(2)+c .  becomes 19 = 4a + 2b + c

Substitute the 5 for c.  Then rewrite

10 = a + b + 5      becomes     5 = a+ b     to eliminate b multiply this be (-2)

(-2)( 5 = a+ b) .to get -10 = -2a - 2b  

19 = 4a + 2b + 5  becomes   14 = 4a + 2b  

_______________  Add these two

14 = 4a + 2b

<u>-10 = -2a - 2b</u><u> </u>    this will eliminate the "b" term

4 = 2a       divide both sides by 2   so you have   a = 2  

substitute in 10=a(1)²+b(1)+5 to find b

10=2(1)²+b(1)+5 .becomes  5 = 2 + b   Subtract 2 from both sides

b = 3

So now you have all three values:  

a = 2  b= 3  c = 5  

I am attaching the graph. I hope this deserves Brainiest.

Best wishes in your studies!

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