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motikmotik
2 years ago
8

This system has one solution. {y=6x−11y=x2+4x−10 what is the y-coordinate of the solution?

Mathematics
2 answers:
Ede4ka [16]2 years ago
8 0

Answer:

y-coordinate of the solution is, -5

Step-by-step explanation:

Given the system of equations:

y = 6x-11

y= x^2+4x-10

Equate these two equations we have;

6x-11 = x^2+4x-10

Subtract 6x from both sides we have;

-11 = x^2-2x-10

Add 11 both sides we have;

0= x^2-2x+1

Using the identity rule:

(a-b)^2 = a^2-2ab+b^2

then;

x^2-2x+1 = 0

⇒(x-1)^2 = 0

⇒x-1 = 0

⇒x = 1

Substitute the value of x in y = 6x-11 we have;

y = 6(1)-11 = 6-11 = -5

therefore, the  y-coordinate of the solution is, -5

Pavel [41]2 years ago
6 0
I took the test and the answer was

-5
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Suppose the weights of apples are normally distributed with a mean of 85 grams and a standard deviation of 8 grams. The weights
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Answer:

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Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Weights of apples are normally distributed with a mean of 85 grams and a standard deviation of 8 grams.

This means that \mu = 85, \sigma = 8

a. Find the probability a randomly chosen apple exceeds 100 g in weight.

This is 1 subtracted by the p-value of Z when X = 100. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{100 - 85}{8}

Z = 1.875

Z = 1.875 has a p-value of 0.9697

1 - 0.9696 = 0.0304

0.0304 = 3.04% probability a randomly chosen apple exceeds 100 g in weight.

b. What weight do 80% of the apples exceed?

This is the 100 - 80 = 20th percentile, which is X when Z has a p-value of 0.2, so X when Z = -0.84.

Z = \frac{X - \mu}{\sigma}

-0.84 = \frac{X- 85}{8}

X - 85 = -0.84*8

X = 78.28

The weight that 80% of the apples exceed is of 78.28g.

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Step-by-step explanation:

i just took the test

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Ugh this hurts my head just looking at it, but I'll show the process.

PEMDAS

Addition before subtraction (Not that it matters here).

2 - (-4) is the same as adding 4.  This equals 6.

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Showing my work...

2 - (-4) + (-1) - (-3)

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3 years ago
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Answer:

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Step-by-step explanation:

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x = 4/30 = 2/15

In one hour, Meagan knit 2/15 of the scarf.

7 0
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