Answer:
Probability that at least 490 do not result in birth defects = 0.1076
Step-by-step explanation:
Given - The proportion of U.S. births that result in a birth defect is approximately 1/33 according to the Centers for Disease Control and Prevention (CDC). A local hospital randomly selects five births and lets the random variable X count the number not resulting in a defect. Assume the births are independent.
To find - If 500 births were observed rather than only 5, what is the approximate probability that at least 490 do not result in birth defects
Proof -
Given that,
P(birth that result in a birth defect) = 1/33
P(birth that not result in a birth defect) = 1 - 1/33 = 32/33
Now,
Given that, n = 500
X = Number of birth that does not result in birth defects
Now,
P(X ≥ 490) =
= + .......+
= 0.04541 + ......+0.0000002079
= 0.1076
⇒Probability that at least 490 do not result in birth defects = 0.1076
Answer:
To entertain
Step-by-step explanation:
Because the dad made a joke to entertain, and the story is entertaining the readers.
It would be multiplication and subtraction
4(x-3)
four times
( the difference of a number “x” and three)
difference means subtraction every time.
Let x = 1st integer.
<span>Equation: </span>
<span>x + x + 1 = 39 </span>
<span>2x = 38 </span>
<span>x = 19 </span>
<span>Answer: 1st integer = 19, 2nd integer = 20, sum = 39.</span>