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ss7ja [257]
2 years ago
8

Pls show me how u did it

Mathematics
2 answers:
eduard2 years ago
7 0

Answer:

(2,1)

Step-by-step explanation:

This is because when you type the equations into desmos, this is the cordinate that they collide.

Hope this answers your question.

topjm [15]2 years ago
7 0

Answer:

(2,1)

Step-by-step explanation:

This is because when you type the equations into desmos, this is the cordinate that they collide.

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Pls help I don't understand this
Rudiy27
<h3>Answer:</h3>

<u>By angle bisector property</u>,

  • 11x + 23 = 8x + 35
  • 11x - 8x = 35 - 23
  • 3x = 12
  • x = 4°

So, <u>m∠ABD</u> = 8x + 35

  • 8 × 4 + 35
  • 32 + 35 = 67°

<u>m∠CBD</u> = 11x + 23

  • 11 × 4 + 23
  • 44 + 23 = 67°

<u>m∠ABC</u> = 67° + 67° = 134°

4 0
3 years ago
Need help with this question, if you don’t know it don’t answer it please
Lerok [7]

Answer:

54

Step-by-step explanation:

9 x 3 x 2 = 54

7 0
3 years ago
Read 2 more answers
Suppose the linear regression line y=2.1x+130 predicts sales based on the money spent on advertising. If x represents the dollar
slega [8]

Linear regression line y=2.1x+130 predicts sales based on the money spent on advertising.

Linear regression represents the relationship between two variables. the value of y depends on the value of x.

x represents the dollars spent in advertising and y represents the company sales in dollars.

We need to find out sales y when $150 spends on advertising.

Plug in 150 for x and find out y

y = 2.1 x + 130

y = 2.1 (150) + 130

y= 445

The company expects $445 in sales

5 0
3 years ago
A = 1011 + 337 + 337/2 +1011/10 + 337/5 + ... + 1/2021
egoroff_w [7]

The sum of the given series can be found by simplification of the number

of terms in the series.

  • A is approximately <u>2020.022</u>

Reasons:

The given sequence is presented as follows;

A = 1011 + 337 + 337/2 + 1011/10 + 337/5 + ... + 1/2021

Therefore;

  • \displaystyle A = \mathbf{1011 + \frac{1011}{3} + \frac{1011}{6} + \frac{1011}{10} + \frac{1011}{15} + ...+\frac{1}{2021}}

The n + 1 th term of the sequence, 1, 3, 6, 10, 15, ..., 2021 is given as follows;

  • \displaystyle a_{n+1} = \mathbf{\frac{n^2 + 3 \cdot n + 2}{2}}

Therefore, for the last term we have;

  • \displaystyle 2043231= \frac{n^2 + 3 \cdot n + 2}{2}

2 × 2043231 = n² + 3·n + 2

Which gives;

n² + 3·n + 2 - 2 × 2043231 = n² + 3·n - 4086460 = 0

Which gives, the number of terms, n = 2020

\displaystyle \frac{A}{2}  = \mathbf{ 1011 \cdot  \left(\frac{1}{2} +\frac{1}{6} + \frac{1}{12}+...+\frac{1}{4086460}  \right)}

\displaystyle \frac{A}{2}  = 1011 \cdot  \left(1 - \frac{1}{2} +\frac{1}{2} -  \frac{1}{3} + \frac{1}{3}- \frac{1}{4} +...+\frac{1}{2021}-\frac{1}{2022}  \right)

Which gives;

\displaystyle \frac{A}{2}  = 1011 \cdot  \left(1 - \frac{1}{2022}  \right)

\displaystyle  A = 2 \times 1011 \cdot  \left(1 - \frac{1}{2022}  \right) = \frac{1032231}{511} \approx \mathbf{2020.022}

  • A ≈ <u>2020.022</u>

Learn more about the sum of a series here:

brainly.com/question/190295

8 0
2 years ago
Read 2 more answers
Please help with this question it is super important
Lunna [17]

Answer:

P=7

Step-by-step explanation:

3 0
4 years ago
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