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xxTIMURxx [149]
3 years ago
13

Francisco has a savings account balance of $2033.88. The interest rate on the account is 2.9% compounded monthly. If he opened t

he account nine years ago, what was the value of his initial deposit?
Mathematics
1 answer:
artcher [175]3 years ago
3 0
The equation for this is:

F = P(1+i)ⁿ
where
F is the present accounts balance
P is the initial deposit
i is the interest rate
n is the number of months

The interest rate is nominal which is 2.9% per year compounded monthly. Since there are 12 months in a year, that is equal to an effective interest rate of 0.24167% per month compounded monthly (i = 0.0024167). In 9 years, there are a total of 108 months, so n=108.

<span>$2033.88 = P(1+0.0024167)</span>¹⁰⁸
P = $1567.147
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Grace [21]

Answer:

option a) 30 : 19

Step-by-step explanation:

Length = 7 \frac{1}{2} = \frac{15}{2}\\\\Width = 4\frac{3}{4} = \frac{19}{4}

<em><u>Ratio of length to width:</u></em>

      \frac{15}{2} : \frac{19}{4}<em><u></u></em>

    =\frac{\frac{15}{2}}{\frac{19}{4}}\\\\=\frac{15}{2 } \times \frac{4}{19}\\\\=15\times \frac{2}{19}\\\\=\frac{30}{19}\\\\30 : 19

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B.(2,1)

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