Answer:
Most people found the probability of just stopping at the first light and the probability of just stopping at the second light and added them together. I'm just going to show another valid way to solve this problem. You can solve these kinds of problems whichever way you prefer.
There are three possibilities we need to consider:
Being stopped at both lights
Being stopped at neither light
Being stopped at exactly one light
The sum of the probabilities of all of the events has to be 1 because there is a 100% chance that one of these possibilities has to occur, so the probability of being stopped at exactly one light is 1 minus the probability of being stopped at both lights minus the probability of being stopped at neither.
Because the lights are independent, the probability of being stopped at both lights is just the probability of being stopped at the first light times the probability of being stopped at the second light. (0.4)(0.7) = 0.28
The probability of being stopped at neither is the probability of not being stopped at the first light, which is 1-0.4 or 0.6, times the probability of not being stopped at the second light, which is 1-0.7 or 0.3. (0.6)(0.3) = 0.18
The probability at being stopped at exactly one light is 1-0.18-0.28=.54 or 54%.
Answer is N/A. There is not a ratio to answer the question.
Answer:
The one opposite of 100°, as the bigger the angle, the bigger the opposing side, is the biggest.
By the same logic, the one opposite 45° is the next biggest.
Continuing with that, the one opposite the black one (which would equal 35°, I think) is the smallest.
Answer:
2
Step-by-step explanation
Either your 5, your just trying brain.ly out, or your trolling don't care either way
Example question: There are 38 students in a baseball club. The coach needs to split them up into equal groups of 4. How many groups can be made? How many kids are left over?
Answer: You would make groups of 4 to get your quotient (9). Then whatever is NOT in a group is your left over.
