Answer:
boom I hope this was the right thing
Step-by-step explanation:
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X=5 because you add 2 to both side and get 3x=15, and then you divide both sides by 3 to get x alone, and get 15/3 which equals 5
GCF of 32 and 48 = 16
32 - 48
16(2 - 3) <==
The area, to the nearst square inch, of a circle the same size az the bicycle wheel is 531 inches².
<h3>What is the area of the circle?</h3>
A circle is a bounded figure which points from its center to its circumference is equidistant.
Area of a circle = πr²
Where :
π = pi = 22/7
R = radius
The full rotation of the wheel is equal to the circumference of the wheel.
circumference of the wheel = 2 πr
26π = 2 πr
r = 13 inches
Area = 22/7 x 13³ = 531 inches²
To learn more about the area of a circle, please check: brainly.com/question/14351152
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Refer to the attached diagram for further a visual explanation. As per the given information, segments (AB) and (AD) are congruent. Moreover, segments (AC) and (AE) are also congreunt. One is also given that angles (<BAD) and (<EAC) are congruent. However, in order to prove the triangles (ABC) and (ADE) are congruent (using side-angle-side) congruence theorem, one needs to show that angles (<BAC) and (<DAE) are congruent. An easy way to do so is to write out angles (<BAC) and (<DAE) as the sum of two smaller angles:
<BAC = <BAD + <DAC
<DAE = <DAC + <EAC
Both angles share angle (DAC) in common, since angles (<EAC) and (BAD) are congruent, angles (<BAC) and (<DAE) must also be congruent.
Therefore triangles (ABC) and (ADE) are congruent by side-angle-side, thus sides (BC) and (DE) must also be congruent.
In summary:
AB = AD Given
AC = AE Given
<BAD = <EAC Given
<DAC = <DAC Reflexive
<BAC = <BAD + <DAC Parts-Whole Postulate
<DAE = <EAC + < DAC Parts-Whole Postulate
<BAC = <DAE Transitivity
ABC = ADE Side-Angle-Side
BC = DE Corresponding parts of congruent triangles are congruent