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Anna007 [38]
3 years ago
8

HELP PLEASE ASAP !!!

Mathematics
1 answer:
Rom4ik [11]3 years ago
8 0
11.y= 300(12)
12. 300x2= 600=24 m so we need 150 more. well 300/2=150 and 12/2= 6 so 24+6=30 30Gal
13. 30x3.75= $112.50
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Simplify the given expression. (16x^2 + 15xy – 19y^2) – (3x^2 – 3xy)
ruslelena [56]

Answer:

-19 y^2 + 18 x y + 13 x^2

Step-by-step explanation:

Simplify the following:

16 x^2 + 15 x y - 19 y^2 - (3 x^2 - 3 x y)

Factor 3 x out of 3 x^2 - 3 x y:

16 x^2 + 15 x y - 19 y^2 - 3 x (x - y)

-3 x (x - y) = 3 x y - 3 x^2:

16 x^2 + 15 x y - 19 y^2 + 3 x y - 3 x^2

Grouping like terms, 16 x^2 + 15 x y - 19 y^2 - 3 x^2 + 3 x y = -19 y^2 + (15 x y + 3 x y) + (16 x^2 - 3 x^2):

-19 y^2 + (15 x y + 3 x y) + (16 x^2 - 3 x^2)

x y 15 + x y 3 = 18 x y:

-19 y^2 + 18 x y + (16 x^2 - 3 x^2)

16 x^2 - 3 x^2 = 13 x^2:

Answer:  -19 y^2 + 18 x y + 13 x^2

4 0
3 years ago
Read 2 more answers
What is the slope of the line<br><br>​
mrs_skeptik [129]

Answer:steepness

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
1. Write a two-column proof.
Alexandra [31]

Answer:

Check it below, please

Step-by-step explanation:

Hi there!

Let's prove segment AB is perpendicular to CD. Attention to the fact that a two column proof has to be concise. So all the comments can't be exhaustive, but as short as possible.

Let's recap: An isosceles triangle is one triangle with at least 2 congruent angles.

Statement                     Reason

\overline{AB} \cong \overline{AC}\\                     Given

\widehat{ACB} \:bisects\: \overline{AB}        Isosceles Triangle the altitude, the bisector coincide.          

\overline{AD} \cong \overline{DB}               Bisector equally divide a line segment into two congruent      

m\angle CDA =m \angle CBD=90^{\circ} Right angles, perpendicular lines.                  

\overline{CD}\perp \overline{AB}                    Perpendicular Line segment      

8 0
3 years ago
Inequality <br> Choose all answers that apply
maxonik [38]

Hi there!  

»»————- ★ ————-««

I believe your answer is:  

Option A;  m \leq\frac{3}{5}

»»————- ★ ————-««  

Here’s why:  

  • We can use inverse operations to solve for 'm'.

⸻⸻⸻⸻

\boxed{\text{Solving for 'm':}}\\\\5m+1\leq4\\--------\\\rightarrow 5m + 1 - 1 \leq 4 - 1\\\\\rightarrow 5m\leq3\\\\\rightarrow \frac{5m\leq3}{5}\\\\\rightarrow \boxed{m\leq\frac{3}{5}}

⸻⸻⸻⸻

Any number that is less than or equal to the value of three-fifths would work.

The option that is less than or equal to (3/5) is option A.

Assuming that there are more options than the options shown, choose the numbers that are less than or equal to (3/5).

»»————- ★ ————-««  

Hope this helps you. I apologize if it’s incorrect.  

8 0
3 years ago
I need help with solving this
leva [86]

Answer:

49

Step-by-step explanation:

Positive 49 not -49

3 0
3 years ago
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