Round 796.301 to the underlined place value.the underlined place value is 0
2 answers:
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Answer:
18 J is the work required to stretch a spring from 7 m to 13 m.
Step-by-step explanation:
The work done is defined to be the product of the force and the distance
that the object moves:
If is measured in newtons and
<em> </em>in meters, then the unit for is a newton-meter, which is called a joule (J).
This definition work as long as the force is constant, but if the force is variable like in this case, we have that the work done is given by
Hooke’s Law states that the force required to maintain a spring stretched units beyond its natural length is proportional to
where is a positive constant (called the spring constant).
To find how much work W is required to stretch it from 7 m to 13 m you must:
Step 1: Find the spring constant
We know that the spring has a natural length of 7 m and a 4 N force is required to keep it stretched to a length of 11 m. So, applying Hooke’s Law
Thus
Step 2: Find the the work done in stretching the spring from 7 m to 13 m.
Recall that the natural length is 7 m, so when we stretch the spring from 7 m to 13 m, we are stretching it by 6 m beyond its natural length.
Work needed to stretch it by 6 m beyond its natural length
18 J is the work required to stretch a spring from 7 m to 13 m.
Answer:
C and D
Step-by-step explanation:
Population density is the ratio of population to area. Its units are persons per square mile. Here, you're being asked to compare the population densities of several countries to the average population density in several US states.
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<h3>average</h3>The idea of "average population density of the 10 states listed" is somewhat ambiguous. It could mean either of (a) the ratio of the total of the states' population to the total of their land area, or (b) the average of the population densities of the states. (In the attached, we computed both, but the answer remains the same using either number.)
When there are numerous identical calculations to be performed, it is convenient to let a spreadsheet do them. The attached spreadsheet shows the population densities for the 10 states and 5 countries listed.
Depending on how you define it, the average population density of the 10 states is about 10.5 or about 15.7 people per square mile. (15.7 is the average of the density numbers, found using the spreadsheet AVERAGE function.)
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<h3>countries</h3>The 5 countries have population densities ranging from about 7.7 to 236 people per square mile. Two of the countries have density below 10.5, so are the answers to the question asked.
Canada (C) and Iceland (D) have population density below the US state average.
