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vfiekz [6]
3 years ago
8

The temperature in anchorage ,Alaska was 4 degrees at 2:00 pm.The temperature dropped 2.5 degrees per hour until 9:00 pm.The tem

perature dropped another 9 degrees by midnight.How much colder was it at midnight than at 2:00 pm?
Mathematics
1 answer:
puteri [66]3 years ago
6 0

Answer:

It was 26.5 degrees colder at midnight than at 2:00 pm

Step-by-step explanation:

We have that:

At 2:pm, it was 4 degrees.

The temperature dropped 2.5 degrees per hour until 9:00 pm.

From 2pm to 9pm, there are 7 hours. 2.5 per hour, it was 4 degrees at 2 pm.

So at 9 pm the temperature is:

4 - 2.5*7 = -13.5

The temperature dropped another 9 degrees by midnight.

At midnight, the temperature is -13.5 - 9 = -22.5 degrees

How much colder was it at midnight than at 2:00 pm?

2pm: 4 degrees

Midnight: -22.5 degrees

How much coldren

-22.5 - 4 = -26.5

It was 26.5 degrees colder at midnight than at 2:00 pm

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= \frac{x}{x^2+3x+2} - \frac{1}{x^2+3x+2}

Since the denominators are common, then subtract the numerators

= \frac{x-1}{x^2+3x+2}

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As we know, sum of interior angles of a triangle is 180°

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How many terms are there in the sequence 1, 8, 28, 56, ..., 1 ?
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Answer:

9 terms

Step-by-step explanation:

Given:  

1, 8, 28, 56, ..., 1

Required

Determine the number of sequence

To determine the number of sequence, we need to understand how the sequence are generated

The sequence are generated using

\left[\begin{array}{c}n&&r\end{array}\right] = \frac{n!}{(n-r)!r!}

Where n = 8 and r = 0,1....8

When r = 0

\left[\begin{array}{c}8&&0\end{array}\right] = \frac{8!}{(8-0)!0!} = \frac{8!}{8!0!} = 1

When r = 1

\left[\begin{array}{c}8&&1\end{array}\right] = \frac{8!}{(8-1)!1!} = \frac{8!}{7!1!} = \frac{8 * 7!}{7! * 1} = \frac{8}{1} = 8

When r = 2

\left[\begin{array}{c}8&&2\end{array}\right] = \frac{8!}{(8-2)!2!} = \frac{8!}{6!2!} = \frac{8 * 7 * 6!}{6! * 2 *1} = \frac{8 * 7}{2 *1} =2 8

When r = 3

\left[\begin{array}{c}8&&3\end{array}\right] = \frac{8!}{(8-3)!3!} = \frac{8!}{5!3!} = \frac{8 * 7 * 6 * 5!}{5! *3* 2 *1} = \frac{8 * 7 * 6}{3 *2 *1} = 56

When r = 4

\left[\begin{array}{c}8&&4\end{array}\right] = \frac{8!}{(8-4)!4!} = \frac{8!}{4!3!} = \frac{8 * 7 * 6 * 5 * 4!}{4! *4*3* 2 *1} = \frac{8 * 7 * 6*5}{4*3 *2 *1} = 70

When r = 5

\left[\begin{array}{c}8&&5\end{array}\right] = \frac{8!}{(8-5)!5!} = \frac{8!}{5!3!} = \frac{8 * 7 * 6 * 5!}{5! *3* 2 *1} = \frac{8 * 7 * 6}{3 *2 *1} = 56

When r = 6

\left[\begin{array}{c}8&&6\end{array}\right] = \frac{8!}{(8-6)!6!} = \frac{8!}{6!2!} = \frac{8 * 7 * 6!}{6! * 2 *1} = \frac{8 * 7}{2 *1} = 28

When r = 7

\left[\begin{array}{c}8&&7\end{array}\right] = \frac{8!}{(8-7)!7!} = \frac{8!}{7!1!} = \frac{8 * 7!}{7! * 1} = \frac{8}{1} = 8

When r = 8

\left[\begin{array}{c}8&&8\end{array}\right] = \frac{8!}{(8-8)!8!} = \frac{8!}{8!0!} = 1

The full sequence is: 1,8,28,56,70,56,28,8,1

And the number of terms is 9

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