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earnstyle [38]
3 years ago
12

Solve for x: 7 over 8 minus 1 over x equals 3 over 4.

Mathematics
1 answer:
photoshop1234 [79]3 years ago
8 0
Hi!

Let's write the equation in number form first.

7 over 8
7/8

minus 1
7/8 - 1

over x
7/8 - 1/x

equals 3
7/8 - 1/x = 3

over 4
7/8 - 1/x = 3/4

Now to find the value, let's put each option as the value for x.

A. x = 1
7/8 - 1/1 = 3/4
7/8 - 1 = 3/4
0.875 - 1 = 0.75
-0.125 = 0.75
This is wrong.

B. x = 2
7/8 - 1/2 = 3/4
7/8 - 0.5 = 3/4
0.875 - 0.5 = 0.75
0.375 = 0.75
This is wrong.

C. x = 4
7/8 - 1/4 = 3/4
7/8 - 0.25 = 3/4
0.875 - 0.25 = 0.75
0.625 = 0.75
This is wrong.

D. x = 8
7/8 - 1/8 = 3/4
7/8 - 0.125 = 3/4
0.875 - 0.125 = 0.75
0.75 = 0.75
This is correct!

The answer is d. x = 8

Hope this helps! :)
-Peredhel



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Please give me the correct answer ​
Ganezh [65]

Answer:

PQ = 5 units

QR = 8 units

Step-by-step explanation:

Given

P(-3, 3)

Q(2, 3)

R(2, -5)

To determine

The length of the segment PQ

The length of the segment QR

Determining the length of the segment PQ

From the figure, it is clear that P(-3, 3) and Q(2, 3) lies on a horizontal line. So, all we need is to count the horizontal units between them to determine the length of the segments P and Q.

so

P(-3, 3), Q(2, 3)

PQ = 2 - (-3)

PQ = 2+3

PQ = 5 units

Therefore, the length of the segment PQ = 5 units

Determining the length of the segment QR

Q(2, 3), R(2, -5)

(x₁, y₁) = (2, 3)

(x₂, y₂) = (2, -5)

The length between the segment QR is:

l=\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}

  =\sqrt{\left(2-2\right)^2+\left(-5-3\right)^2}

  =\sqrt{0+8^2}

  =\sqrt{8^2}

Apply radical rule: \sqrt[n]{a^n}=a,\:\quad \mathrm{\:assuming\:}a\ge 0

  =8

Therefore, the length between the segment QR is: 8 units

Summary:

PQ = 5 units

QR = 8 units

8 0
2 years ago
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