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3 years ago

PLEASE HELP ASAP 25 PTS + BRAINLIEST TO RIGHT/BEST ANSWER

Mathematics

1 answer:

Rasek [7]3 years ago

5 0

Answer:

113-2t√17

Step-by-step explanation:

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Please help with this :D

jarptica [38.1K]

Answer:

130°-85°=45°

x=45°

Hope it will help you

3 0

3 years ago

The exponent indicates how many times the ......... is used as a factor

Dimas [21]

Base or base number
for example 2^3 = 2 * 2 * 2 or x^2 = x * x

7 0

3 years ago

{18 • [(25 + 15) ÷ 4] + 25} • 12 + 16 • 3

Leviafan [203]

2,508 says my calulator

3 0

3 years ago

Read 2 more answers

If 5 + 20 times 2 Superscript 2 minus 3 x Baseline = 10 times 2 Superscript negative 2 x Baseline + 5, what is the value of x? –

sp2606 [1]

Answer:

<h3>Option D) 3 is correct</h3><h3>Therefore the value of x is 3</h3>

Step-by-step explanation:

Given equation is $5+20\times (2)^{2-3x}=10\times (2)^{-2x}+5$

<h3>To find the value of x :</h3>

First solving the given equation we have,

$5+20\times (2)^{2-3x}=10\times (2)^{-2x}+5$

$5+20\times (2)^{2-3x}-5=10\times (2)^{-2x}+5-5$

$20\times (2)^{2-3x}=10\times (2)^{-2x}$

$20\times (2)^2.(2)^{-3x}=10\times (2)^{-2x}$

$20\times 4.(2)^{-3x}=10\times (2)^{-2x}$

$80(2)^{-3x}=10\times (2)^{-2x}$

$\frac{80}{10}(2)^{-3x}=\frac{10\times (2)^{-2x}}{10}$

$8(2)^{-3x}=(2)^{-2x}$

$\frac{(2)^{-3x}}{(2)^{-2x}}=\frac{1}{8}$

$(2)^{-3x}.(2)^{2x}=\frac{1}{2^3}$ ( by using the property $\frac{1}{a^{-m}}=a^m$ )

$2^{-3x+2x}=\frac{1}{2^3}$ ( by using the property $a^m.a^n=a^{m+n}$ )

$2^{-x}=\frac{1}{2^3}$

$\frac{1}{2^x}=\frac{1}{2^3}$ ( by using the property $a^{-m}=\frac{1}{a^m}$ )

Since bases are same so powers are same

Therefore we can equate the powers we get x=3

<h3>Therefore the value of x is 3</h3><h3>Option D) 3 is correct</h3>

5 0

3 years ago

Read 2 more answers

Two 6-sided dice are rolled. what is the probability that the sum of the two numbers on the dice will be greater than 8?

Serhud [2]

Answer: 5/18

Step-by-step explanation:

The sample space when two 6- sided dice are rolled is given below:

(+) 1 2 3 4 5 6

1 2 3 4 5 6 7

2 3 4 5 6 7 8

3 4 5 6 7 8 9

4 5 6 7 8 9 10

5 6 7 8 9 10 11

6 7 8 9 10 11 12

The total sample space is 36.

Sum greater than 8 are : {9,10,11,12}

which are 10 in number:

Therefore : the probability that the sum of the two numbers on the dice will be greater than 8 will be :

number of the sum greater than 8 / Total sample space

That is ;

P(sum greater than 8) = 10/36

P(sum greater than 8) = 5/18

6 0

3 years ago