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2 years ago

X-4=10;4x+1=57i need to change the first equation into to the second equation.

Mathematics

1 answer:

cestrela7 [59]2 years ago

4 0

Is this what you mean this is what i understood.

X-4=10;4x+1=57

First equation solve for x.

X-4=10

Add 4 both sides

X=10+4

X=14

Second equation substitute your x answer into second equation to make both sides equal.

4x+1=57

4(14)+1=57

56+1=57

57=57

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3 years ago

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3 years ago

Read 2 more answers

4. A sports car accelerates from rest to a final velocity of 64 m/s at a rate of 12.3

Ivanshal [37]

Answer:

$t = 5.2\ s$

Step-by-step explanation:

Given

$a= 12.3m/s^2$ --- acceleration

$v = 64m/s$ --- final velocity

$u =0m/s$ --- initial velocity (it is 0, because the car starts from rest)

Required

Determine the time taken

This will be solved using Newton's first equation of motion:

$v = u + at$

Substitute values for v, u and a

$64 = 0 + 12.3*t$

$64 = 12.3t$

$12.3t = 64$

Make t the subject

$t = \frac{64}{12.3}$

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6 0

2 years ago

Select the correct answer

solong [7]

Answer: OPTION C.

Step-by-step explanation:

Given the functions:

$f(x)=2x^2-x-6\\\\g(x)=x^2-4$

We need to divide f(x) by g(x) in order to find $f(x)$ ÷ $g(x)$ . Then:

$f(x)$ ÷ $g(x)$ $=\frac{2x^2-x-6}{x^2-4}$

Factorizing and simplifying, we get:

$f(x)$ ÷ $g(x)$ $=\frac{(2x+3)(x-2)}{(x+2)(x-2)}$

$f(x)$ ÷ $g(x)$ $=\frac{2x+3}{x+2}$

3 0

2 years ago