Here we have a case of the least common multipl(lcm) of 6 and 20.
Prime numbers 2,3,5,7,11,13,17,19... (natural numbers greater than 1 that has no positive divisors other than 1 and itself) .
lcm(6,20)= 6 20 | 2
3 10 | 3
1 10 | 2
5 | 5
1
2*3*2*5=60 The first one to get both calendar and the animal toy will be 60th.
Explenation: First we look for the smallest prime number with wich 6 and 20 can be devided by. That is 2. Next is 3. Since 10 is not divisible by 3, we only copy it. Under the 6 we got 1, wich is our goal. Now we continue to devide 10 by prime numbers till we also get 1. We now multiple all divisors and we get the least common multiple.
One may note, you never quite asked anything per se, ahemm, if you meant simplification.
Question: A Football Team Charges $30 Per Ticket And Averages 20,000 People Per Game. Each Person Spends An Average Of $8 On Concessions. For Every Drop Of $1 In Price, The Attendance Rises By 800 People. What Ticket Price Should The Team Charge To Maximize Total Revenue? Calculate The TR Max.
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A football team charges $30 per ticket and averages 20,000 people per game. Each person spends an average of $8 on concessions. For every drop of $1 in price, the attendance rises by 800 people. What ticket price should the team charge to maximize total revenue? Calculate the TR max.
$50
