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maria [59]
3 years ago
13

X-4=10;4x+1=57i need to change the first equation into to the second equation.

Mathematics
1 answer:
cestrela7 [59]3 years ago
4 0

Is this what you mean this is what i understood.



X-4=10;4x+1=57


First equation solve for x.

X-4=10

Add 4 both sides

X=10+4


X=14

Second equation substitute your x answer into second equation to make both sides equal.

4x+1=57

4(14)+1=57

56+1=57

57=57

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A clothing store sold 4 times as many sweaters as coats. The difference in the sales was 300. How many of each were sold?
slava [35]
Sweater = 400
coats = 100
difference= 300
in an equation it would be
4x-x=300
so
3x=300
x=100
sweaters= 4x= 400
coats= x= 100
5 0
3 years ago
Help me plz plzz i’m confused
Lisa [10]

a

Step-by-step explanation:

you are trying to divide x by 7 to isolate x. so you divide by 8 on both sides.

8 0
3 years ago
If w varies inversely with the square root of t and w = 5 when t = 49,
VARVARA [1.3K]

Answer:

x=k/y

w=k/t

5=k/√49

5=k/7

k=5×7

k=35

5 0
3 years ago
(1 point) Newton's law of cooling states that the temperature of an object changes at a rate proportional to the difference betw
slavikrds [6]

Answer:

a. \frac{dT}{dt}=k(T-Tm); T(0)=190

b. C_{0}=122

c. k=-0.00259

d. t=153.39838\\ minutos

Step-by-step explanation:

a. Newton's law of cooling states that the speed with which a body is cooled is proportional to the difference between its temperature and that of the medium in which it is found. Then, the initial value problem is given by:

Tm=68

\frac{dT}{dt}=k(T-Tm); T(0)=190

b. The differential equation obtained is a differential equation of separable variables:

\frac{dT}{T-Tm}=kdt\\\\\int {\frac{dT}{T-Tm}}=\int{kdt}\\\\Ln|T-Tm|=kt+C\\\\T(t)=C_{0}e^{kt}+Tm=C_{0}e^{kt}+68\\\\T(0)=C_{0}e^{k(0)}+68=190\\\\C_{0}=122

c. After 33 minutes of serving the coffee has cooled to 180°:

T(33)=122e^{33k}+68=180\\\\e^{33k}=\frac{112}{122}\\\\33k=Ln(\frac{112}{122})\\\\k=-0.00259

d.

150=122e^{-0.00259t}+68\\\\Ln(\frac{150-68}{122})=-0.00259t\\\\t=153.39838\\\\

8 0
3 years ago
Write an equation for a line perpendicular to y = 5x - 4 and passing through the point (15,-1)
VLD [36.1K]

Answer:

y = -1/5 x + 2

Step-by-step explanation:

y = 5x - 4

m = 5

Slope of perpendicular = -1/5

Equation of perpendicular:

y = mx + b

y = -1/5 x + b

Use point (15, -1) for x and y, and solve for b.

-1 = -1/5(15) + b

-1 = -3 + b

b = 2

Equation of perpendicular:

y = -1/5 x + 2

4 0
2 years ago
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