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2 years ago

Which most closely estimates 387÷19?

Mathematics

1 answer:

steposvetlana [31]2 years ago

6 0

Answer:

the answer is 20 with a remainder of 7

Step-by-step explanation:

hope this helps if not let me know

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22. The perimeter of a rectangle is 84 inches and the width is 7 inches.

m_a_m_a [10]

Answer:

35 inches

Step-by-step explanation:

The perimeter of a rectangle is given by

P = 2(l+w)

We know the perimeter and the length

84= 2 ( l+7)

Divide each side by 2

84/2 = 2/2 (l+7)

42 = (l+7)

Subtract 7 from each side

42-7 = l+7-7

35 = l

The length is 35 inches

5 0

3 years ago

Read 2 more answers

Meg has 26 toy ponies she gets 6 more for her birthday she displays half of them on a shelf and puts the rest in a box how many

otez555 [7]

Because Meg gets an additional 6 ponies, she adds them to her existing 26 ponies. This makes her have 32 ponies.
(CHECK: 26+6=32, 32-6=26)

Since she displays half of her 32, that means 16 of her ponies are on display.
(CHECK: 32/2=16, 16+16=32)

Hopefully this helps!! :)

8 0

3 years ago

Read 2 more answers

2 1/3x4 1/5 in simplest form

telo118 [61]

Answer:

${ \tt{2 \frac{1}{3} \times 4 \frac{1}{5} }} \\ \\ = { \tt{ \frac{7}{3} \times \frac{21}{5} }} \\ \\ = { \tt{ \frac{147}{15} }} \\ \\ = \frac{49}{5} \\ \\ = 9 \frac{4}{5}$

3 0

3 years ago

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Daniel bought 30 tokens. he won 8 more tokens for getting highest score at the basket ball contest, but lost 6 tokens on the rin

Alika [10]

30-8+6 is the expression

8 0

3 years ago

A national manufacturer of ball bearings is experimenting with two different processes for producing precision ball bearings. It

lapo4ka [179]

Answer:

A. As we are trying to test if the two processes yield different average errors, we are interested in any of the two posibilities: the average error of process A being statistically significant lower or bigger than the average error of Process B. That is why this is a two-tailed test.

B. t=-3.144

C. The critical value for a significance level of 0.05, a two tailed test with 4 degrees of freedom is t=±2.064.

D. P-value = 0.004

E. Reject H0

F. The probability of making a Type I error is equal to the significance level: P(Type I error) = 0.05.

Step-by-step explanation:

This is a hypothesis test for the difference between populations means.

The claim is that the two processes yield different average errors.

As we are trying to test if the two processes yield different average errors, we are interested in any of the two posibilities: the average error of process A being statistically significant lower or bigger than the average error of Process B. That is why this is a two-tailed test.

Then, the null and alternative hypothesis are:

$H_0: \mu_1-\mu_2=0\\\\H_a:\mu_1-\mu_2\neq 0$

being μ1: average error for Process A and μ2: average error fo Process B.

The significance level is 0.05.

The sample 1, of size n1=12 has a mean of 2 and a standard deviation of 1.

The sample 1, of size n1=14 has a mean of 3 and a standard deviation of 0.5.

The difference between sample means is Md=-1.

$M_d=M_1-M_2=2-3=-1$

The estimated standard error of the difference between means is computed using the formula:

$s_{M_d}=\sqrt{\dfrac{\sigma_1^2}{n_1}+\dfrac{\sigma_2^2}{n_2}}=\sqrt{\dfrac{1^2}{12}+\dfrac{0.5^2}{14}}\\\\\\s_{M_d}=\sqrt{0.083+0.018}=\sqrt{0.101}=0.318$

Then, we can calculate the t-statistic as:

$t=\dfrac{M_d-(\mu_1-\mu_2)}{s_{M_d}}=\dfrac{-1-0}{0.318}=\dfrac{-1}{0.318}=-3.144$

The degrees of freedom for this test are:

$df=n_1+n_2-1=12+14-2=24$

The critical value for a significance level of 0.05, a two tailed test with 4 degrees of freedom is t=±2.064.

This test is a two-tailed test, with 24 degrees of freedom and t=-3.144, so the P-value for this test is calculated as (using a t-table):

$P-value=2\cdot P(t$

As the P-value (0.004) is smaller than the significance level (0.05), the effect is significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the two processes yield different average errors.

5 0

3 years ago