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2 years ago

10

How to solve for x/ extraneous solutions

1 answer:

taurus [48]2 years ago

3 0

Answer:

<h2>x = 8</h2>

Step-by-step explanation:

$\log_ab=c\iff a^c=b\\\\===================\\\\Domain:\ 8x>0\to x>0\\\\\log_4(8x)=3\iff4^3=8x\\\\8x=64\qquad\text{divide both sides by 8}\\\\x=8\in D$

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There are 12 students in a classroom, including the triplets joey, chloe, and zoe. If 3 of the 12 are randomly selcted to give s

BARSIC [14]

The probability of Joey being first is 1/12. If that happens the probability of Chloe going next is 1/11. Then the probability of zoe being picked next would be 1/10. Then if you multiply all the fractions I gave you you would get 1/1320 which is A. So A. Is your answer!! Hope this helps you out!!

8 0

3 years ago

Read 2 more answers

Find all real solutions to the equation (x² − 6x +3)(2x² − 4x − 7) = 0.

Jet001 [13]

Answer:

x = 3 + √6 ; x = 3 - √6 ; $x = \frac{2+3\sqrt{2}}{2}$ ; $x = \frac{2-(3)\sqrt{2}}{2}$

Step-by-step explanation:

Relation given in the question:

(x² − 6x +3)(2x² − 4x − 7) = 0

Now,

for the above relation to be true the following condition must be followed:

Either (x² − 6x +3) = 0 ............(1)

or

(2x² − 4x − 7) = 0 ..........(2)

now considering the equation (1)

(x² − 6x +3) = 0

the roots can be found out as:

$x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}$

for the equation ax² + bx + c = 0

thus,

the roots are

$x = \frac{-(-6)\pm\sqrt{(-6)^2-4\times1\times(3)}}{2\times(1)}$

or

$x = \frac{6\pm\sqrt{36-12}}{2}$

or

$x = \frac{6+\sqrt{24}}{2}$ and, x = $x = \frac{6-\sqrt{24}}{2}$

or

$x = \frac{6+2\sqrt{6}}{2}$ and, x = $x = \frac{6-2\sqrt{6}}{2}$

or

x = 3 + √6 and x = 3 - √6

similarly for (2x² − 4x − 7) = 0.

we have

the roots are

$x = \frac{-(-4)\pm\sqrt{(-4)^2-4\times2\times(-7)}}{2\times(2)}$

or

$x = \frac{4\pm\sqrt{16+56}}{4}$

or

$x = \frac{4+\sqrt{72}}{4}$ and, x = $x = \frac{4-\sqrt{72}}{4}$

or

$x = \frac{4+\sqrt{2^2\times3^2\times2}}{2}$ and, x = $x = \frac{4-\sqrt{2^2\times3^2\times2}}{4}$

or

$x = \frac{4+(2\times3)\sqrt{2}}{2}$ and, x = $x = \frac{4-(2\times3)\sqrt{2}}{4}$

or

$x = \frac{2+3\sqrt{2}}{2}$ and, $x = \frac{2-(3)\sqrt{2}}{2}$

Hence, the possible roots are

x = 3 + √6 ; x = 3 - √6 ; $x = \frac{2+3\sqrt{2}}{2}$ ; $x = \frac{2-(3)\sqrt{2}}{2}$

7 0

2 years ago

Only 18 people are allowed on a ride at the same time. There are 157 people waiting in line. How many groups of riders will ther

IrinaK [193]

Answer:

Step-by-step explanation:

Divide 157 by 8 to see how many groups there are.

157/18=8r13. So you can round up to 9 groups of riders as there is a max of 18 at a time.

7 0

2 years ago

Gina Chuez has considered starting her own custom greeting card business. With an initial start up cost of $1500, she figures it

nordsb [41]

1500 + 0.45x < 1.70x
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3 years ago

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Given the equation 5(-2x -10) = 25(x + 1), solve for the value of x that will make the equation true.

brilliants [131]

Answer:

Step-by-step explanation:

5(-2x -10) = 25(x + 1)

-10x - 50 = 25x + 25

by transposing

-10x - 25x = 25 + 50

-35x = 75

x = -75/35

<u><em>x = 15/7</em></u>

or 2.142857..... in decimal

Hope this helps

plz mark as brainliest!!!!!!!

8 0

3 years ago